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3 years ago

Rudo is making pizzas he needs 3/4 cup of cheese to make one whole pizza. he has 3/8 cup of cheese?

Mathematics

2 answers:

Mamont248 [21]3 years ago

8 0

He need 3/8 more to complete the 3/4 he needs

Aleksandr [31]3 years ago

7 0

Answer is below

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A carpenter wants to expand a square room. The new room will have one side 4 feet longer and the adjacent side 6 feet longer tha

gogolik [260]

Answer:

Dimensions of original room = 12 x 12 feet.

Explanation:

Let the size of old square room be a x a.

New dimension = ( a+4 ) x ( a + 6 )

We have area of the new room will be 144 square feet greater than the area of the original room.

So, ( a+4 ) x ( a + 6 ) = a x a + 144

a²+10a+24= a²+144

10a = 120

a = 12 feet.

Dimensions of original room = 12 x 12 feet.

8 0

3 years ago

Can you simplify 37/80

Setler [38]

Answer:

Step-by-step explanation:

37 is prime, so it's not possible to reduce/simplify 37/80. 37/80 is the ratio of two integers. We could, of course, use a calculator to find the decimal equivalent: 0.4625, but this is not more accurate than the ratio 37/80.

7 0

2 years ago

Mr. Alvarez has 36 kids in his 7th period class The ratio of boys to girls is 5:7. How many boys are there? How many girls are t

Eddi Din [679]

Answer: 15 boys

Explanation: ratio 5:7

5 + 7 = 12

Number of boys = 5/12 × 36

4 0

3 years ago

Mrs. Jones has a local bakery. Last week this expression shows how many peanut butter cupcakes she baked. 5 (2x -4) + 3(3 + 4x)

3241004551 [841]

Answer:

A. $22x-11$

B. $121$ cupcakes

Step-by-step explanation:

Part A:

The simplified form of the expression is

$5(2x-4)+3(3+4x)$

$(10x-20)+(9+12x)$

$(10x+12x)+(9-20)$

$22x-11$

Part B:

Put $x=6$ in the above simplified equation to get the number of cupcakes Mrs. Jones bake last week

$22x-11$

$22(6)-11$

$132-11$

$121$ cupcakes

8 0

4 years ago

F=e−yi−xe−yj is conservative. find a scalar potential f and evaluate the line integral over any smooth path c connecting a(0,0)

Alexxx [7]

If $\mathbf F$ is conservative, then there is a scalar function $f$ such that

$\nabla f(x,y)=\mathbf F(x,y)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j=e^{-y}\,\mathbf i-xe^{-y}\,\mathbf j$

Setting the first components equal to one another, we can integrate both sides to find

$\dfrac{\partial f}{\partial x}=e^{-y}\implies f(x,y)=xe^{-y}+g(y)$

Differentiating both sides with respect to $y$ gives

$\dfrac{\partial f}{\partial y}=-xe^{-y}+\dfrac{\mathrm dg}{\mathrm dy}=-xe^{-y}$
$\implies\dfrac{\mathrm dg}{\mathrm dy}=0$
$\implies g(y)=C$

so that

$f(x,y)=xe^{-y}+C$

By the fundamental theorem of calculus, we have that

$\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=\int_{\mathcal C}\nabla f\cdot\mathrm d\mathbf r=f(1,1)-f(0,0)=\frac1e$

4 0

3 years ago