<span>Volume of Cone:
1/3 Bh where B is the area of the base
1/3 Bh = 5
Bh = 15
B = 15/h
The cylinder has the same base area as the cone.
Volume of Cylinder:
V = B*h
B = V/h and B = 15/h
The height of the cone and the cylinder are the same.
V/h = 15/h
Volume of Cylinder = 15.</span>
Step-by-step explanation:
it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).
what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.
since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).
and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.
AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).
the area of this triangle AOB is
1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =
= 3.897114317... m²
a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).
so, it's area is
pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²
so, the total area of the shaded area is
3.897114317... m² + 4.71238898... m² =
= 8.609503297... m²
Answer:can't see no 1
Step-by-step explanation:
2=A
3=c
Answer:
Step-by-step explanation:
To find your answer you first have to multiply the numbers that aren’t in parentheses and you multiply 2 and 7 and you get 14 then you don’t have to worry about the x because it is a variable so now add -4 +2. but first we have to turn negative into positive so you add -4 + 8
To find the area of this figure, there is two choices
1. cut it into 3 rectangles.
2.find the missing rectangle in the middle......
I likes 2 better $_$ :}
find the missing area in the middle, 12* 23 = 276
the area of the whole figure 31*69-276=1863m²
