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3 years ago

What is the surface area of the square pyramid represented by the net below?

Mathematics

1 answer:

4vir4ik [10]3 years ago

6 0

Answer:

64 cm^2

Step-by-step explanation:

Square: 4*4 = 16

Triangles: 4((4*6)/2))

= 4(24/2)

= 4(12)

= 48

Add the square and triangles together

= 16 + 48

= 64

The total will be 64 cm^2

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|-4| - 8 + 10 = ???<br> answer for points

Elis [28]

Answer:

Step-by-step explanation:

As you might know, the two lines surrounding the -4 represent the absolute value, which is basically the distance from 0, and the distance is always positive. To clear any confusion, the absolute value of positive number will not be it's opposite because remember, distance is always positive, so absolute value is always positive (because it is basically the distance from zero).

To help, here is an example (that is not related to the problem!):

|-6| = 6

|6| = 6

<em>Now, back to the problem...</em>

Since you now know that the absolute value is always positive, |-4| would equal 4. So now you have:

4 - 8 + 10 = ???

From here, you can just solve and the answer is 6, so:

4 - 8 + 10 = 6

You final answer is 6.

Hope this helped somehow :D

4 0

3 years ago

Read 2 more answers

Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th

VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

$f(x)=16-\frac{x^2}{3}$

To find $f(-64)$ , we substitute $x=-64$ into the function.

$f(-64)=16-\frac{(-64)^2}{3}$

$f(-64)=16-\frac{4096}{3}$

$f(-64)=-\frac{4048}{3}$

To find $f(64)$ , we substitute $x=64$ into the function.

$f(64)=16-\frac{(64)^2}{3}$

$f(64)=16-\frac{4096}{3}$

$f(64)=-\frac{4048}{3}$

To find $f'(c)$ , we must first find $f'(x)$ .

$f'(x)=-\frac{2x}{3}$

This implies that;

$f'(c)=-\frac{2c}{3}$

$f'(c)=0$

$\Rightarrow -\frac{2c}{3}=0$

$\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}$

$c=0$

For this function to satisfy the Rolle's Theorem;

It must be continuous on $[-64,64]$ .

It must be differentiable on $(-64,64)$ .

and

$f(-64)=f(64)$ .

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0

3 years ago

Read 2 more answers

6. The first six terms in a quadratic pattern are

dexar [7]

Since 83-59=24, 83 is added by 28 so your answer would be 111.

5 0

3 years ago

What is the slope of this line?

Marysya12 [62]

Answer:

1/4