suppose you have 1000 gallons of gasoline 20% is premium and 80% is regular how much premium gas needs to be added to bring the
1 answer:
20% of 1000 gal = 200 gal of premium gasoline
80% of 1000 gal = 800 gal of regular gasoline
x = volume of premium gasoline that you need to add to the current mixture
60% of the new mixture is supposed to be premium gasoline. The new mixture would have a total volume of (1000 + x) gal, and in this total, you'd have (200 + x) gal of premium gasoline. So
You'd need to add 1000 gal of premium gasoline to get a mixture of 60% premium.
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Drawing it out, as seen, using the Pythagorean theorem we get that w^2+l^2 (with w=width and l=length)=diagonal^2=24^2+l^2=40^2. Subtracting 24^2 from both sides, we get 40^2-24^2=l^2=1024. Square rooting both sides, we get l=32. Since the perimeter is 2w+2l, we get 32*2+24*2=64+48=112
