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Rama09 [41]
3 years ago
9

What do i type? please help me.

Mathematics
2 answers:
Rudiy273 years ago
7 0
Put in any two numbers less than 29 like -29, 23, 17, 6, or any number less than 29
sergij07 [2.7K]3 years ago
4 0

Answer:

x = 10; x = 0

Step-by-step explanation:

x < 29 means x is less than 29. Any number less then 29 is a solution.

For example, pick x = 10. Since 10 < 29, x = 10 is a solution. How do we know x = 10 is a solution?

We start with x < 29.

Now replace x with 10.

10 < 29

Since 10 < 29 is a true statement, then x = 10 is a solution.

Now pick another number less than 29. For example, oick 0.

x = 0 is a solution.

Proof:

x < 29

Replace x with 0:

0 < 29

Since 0 < 29 is a true statement, then x = 0 is a solution.

You can give more solutions just by picking any numbers that are less than 29, such as 1, 2, 3, 15, 28, 23, -5, -18, etc.

Answer: x = 10; x = 0

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find the volume of each sphere, both in terms of pi and to the nearest tenth. use 3.14 for pi r = 6.12 cm d = 54 in
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The shape in the figure is a square. Use the properties of a square to determine the value of x.
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f(x)=a(1+r)^x

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\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}

And 1976 is n=16

\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}

Solve the two equations simultaneously, as shown below

\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}

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a) Thus, the equation is

\Rightarrow f(n)=1.113043\ldots(1+0.0464078\ldots)^n

b) 1960 is n=0; thus,

f(0)=1.113043\ldots(1+0.0464078\ldots)^0=1.113043\ldots

The answer to part b) is $1.113043... per hour

c)1996 is n=36

\begin{gathered} f(36)=1.113043\ldots(1+0.0464078\ldots)^{36} \\ \Rightarrow f(36)=5.6983\ldots \end{gathered}

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