A picture has a height that is 2 times it’s width . It is to be enlarged to an area of 128 in 2
1 answer:
9514 1404 393
Answer:
8 in by 16 in
Step-by-step explanation:
In your equation, we presume that x represents the width. Solving for x, we have ...
2x² = 128 . . . . . . given equation
x² = 64 . . . . . . . . divide by 2
x = √64 = 8 . . . . square root
The enlargement will be 8 inches by 16 inches.
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7.6x = 64
x = 64/7.6
x =
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8.4210526316
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So, 3.05 is NOT the solution
What do you need help with and what subject
Answer:
3.4
Step-by-step explanation:
will 3.4 is is rounded of 54256 in decamal
Answer:
-6x
Step-by-step explanation:
Answer:
f your number is x, then the difference between that number and 8 would be x-8. Twice that is 2(x-8)
Three times the sum of the number and 3 would be 3(x+3). So, you get the equation:
2(x-8)=3(x+3)
2x-16=3x+9
x=-25
