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3 years ago

Help me out, please....

Mathematics

2 answers:

alex41 [277]3 years ago

8 0

Answer:

5 radical 3

Step-by-step explanation:

b = √c2 - a2

= √102 - 52

= √75

= 8.66025 = 5√3

melomori [17]3 years ago

4 0

Answer: D

Step-by-step explanation:

Using Pythagoras’ theorem

H^2= O^2 + A^2

H= 10

O= 5

A= x

A^2= H^2 - O^2

x^2= 10^2 - 5^2

x^2= 100 - 25

x^2= 75

x= 75^(1/2)

x= 5(3^(1/2))

x= 5 √3

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Sidney is making greeting cards, which she will sell by the box at an arts fair. She paid $32 for a booth at the fair, and the m

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So think of it like this she starts off $32 negative and subtract 3 from each box of cards she makes . So each box of cards she will make $8 that being said

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Which in total would be $64

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Step-by-step explanation:

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larisa86 [58]

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3 years ago

a pipe is leaking at 1.5 cups per day. about how many gallons per week is the pipe leaking? (HINT : 1 gallon = 16 Oz)

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3 0

3 years ago

In a recent Super Bowl, a TV network predicted that 50 % of the audience would express an interest in seeing one of its forthcom

coldgirl [10]

Answer:

z= -0.968

We can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they would watch one of the television shows not differs from 0.5 or 50% .

Step-by-step explanation:

1) Data given and notation n

n=106 represent the random sample taken

X=48 represent the people who says that they would watch one of the television shows.

$\hat p=\frac{48}{106}=0.453$ estimated proportion of people who says that they would watch one of the television shows.

$p_o=0.5$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 50% of people who says that they would watch one of the television shows.:

Null hypothesis: $p=0.5$

Alternative hypothesis: $p \neq 0.5$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.453 -0.5}{\sqrt{\frac{0.5(1-0.5)}{106}}}=-0.968$

4) Statistical decision

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided, but we can assume $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they would watch one of the television shows not differs from 0.5 or 50% .

6 0

3 years ago