Question

HELP pythagorean identity

Answer 1

Answer:

sin x

Step-by-step explanation:

sin ^2  x + sin x + cos ^ x -1

sin ^2  x + cos ^ x   + sin x-1

We know that sin^2 x + cos ^2 x = 1

1 + sin x -1

sin x

Answer 2

Hi!

$\sin^2x+\sin x+\cos^2 x-1=\\\\=\underline{\sin^2x+\cos^2x}+\sin x-1=\\\\=1+\sin x-1=\boxed{\sin x}$