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AnnZ [28]
3 years ago
15

This graph shows the cost of a small cheese pizza at 3 different restaurants. a) explain how the size of the bars gives a false

impression about the cost of the pizza at different restaurants.
Mathematics
1 answer:
nlexa [21]3 years ago
8 0

I would answer, but I don’t see the graph. If you add the graph I could help (if you want of course, not trying to be rude. Sorry!)

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Fastest answer gets brainiest !
saveliy_v [14]

Answer:

  • A. 1/16

Step-by-step explanation:

<u>The most repeated value is:</u>

  • (1/4)/4 = 1/16

There are 4 of them.

Correct choice is A

3 0
3 years ago
What is wrong with the following proof that for every integer n, there is an integer k such that n &lt; k &lt; n + 2? Suppose n
expeople1 [14]

Answer:

c)The proof writer mentally assumed the conclusion. He wrote "suppose n is an arbitrary integer", but was really thinking "suppose n is an arbitrary integer, and suppose that for this n, there exists an integer k that satisfies n < k < n+2." Under those assumptions, it follows indeed that k must be n + 1, which justifies the word "therefore": but of course assuming the conclusion destroyed the validity of the proof.

Step-by-step explanation:

when we claim something as a hypothesis we can only conclude with therefore at the end of the proof. so assuming the conclusion nulify the proof from the beginning

4 0
3 years ago
42+30=[BLANK](7+5)<br> 20 POINTS!!
qaws [65]

Answer:

42+30=72

7+5=12

72-12=60

Blank=60

Step-by-step explanation:

4 0
3 years ago
N+10=8<br> What does N=?
Aleks04 [339]

Answer:

N= -2

Step-by-step explanation:

N+10=8

   -10= -10

        N= -2

4 0
2 years ago
Read 2 more answers
Simplify the expression csc(-x)/1+tan^2x)
Charra [1.4K]
Assuming ya meant \frac{csc(-x)}{1+tan^2(x)}

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos


for the pythaogreaon identity
cos^2(x)+sin^2(x)=1
divide both sides by cos^2(x)
1+tan^2(x)=sec^2(x) since \frac{sin(x)}{cos(x)}=tan(x)
subsitute
\frac{csc(x)}{sec^2(x)}

recall that csc(x)=\frac{1}{cos(x)}
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)
so we get

\frac{csc(x)}{sec^2(x)}
decompose them into \frac{1}{cos(x)} and \frac{1}{sin^2(x)} to get \frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}
multiply by \frac{sin^2(x)}{sin^2(x)} to get
\frac{sin^2(x)}{cos(x)}
we can furthur simlify to get
(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)
the expression simplifies to tan(x)sin(x)
5 0
3 years ago
Read 2 more answers
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