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3 years ago

15

This graph shows the cost of a small cheese pizza at 3 different restaurants. a) explain how the size of the bars gives a false

impression about the cost of the pizza at different restaurants.

1 answer:

nlexa [21]3 years ago

8 0

I would answer, but I don’t see the graph. If you add the graph I could help (if you want of course, not trying to be rude. Sorry!)

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Fastest answer gets brainiest !

saveliy_v [14]

Answer:

A. 1/16

Step-by-step explanation:

<u>The most repeated value is:</u>

(1/4)/4 = 1/16

There are 4 of them.

Correct choice is A

3 0

3 years ago

What is wrong with the following proof that for every integer n, there is an integer k such that n < k < n + 2? Suppose n

expeople1 [14]

Answer:

c)The proof writer mentally assumed the conclusion. He wrote "suppose n is an arbitrary integer", but was really thinking "suppose n is an arbitrary integer, and suppose that for this n, there exists an integer k that satisfies n < k < n+2." Under those assumptions, it follows indeed that k must be n + 1, which justifies the word "therefore": but of course assuming the conclusion destroyed the validity of the proof.

Step-by-step explanation:

when we claim something as a hypothesis we can only conclude with therefore at the end of the proof. so assuming the conclusion nulify the proof from the beginning

4 0

3 years ago

42+30=[BLANK](7+5)<br> 20 POINTS!!

qaws [65]

Answer:

42+30=72

7+5=12

72-12=60

Blank=60

Step-by-step explanation:

4 0

3 years ago

N+10=8<br> What does N=?

Aleks04 [339]

Answer:

N= -2

Step-by-step explanation:

N+10=8

-10= -10

N= -2

4 0

2 years ago

Read 2 more answers

Simplify the expression csc(-x)/1+tan^2x)

Charra [1.4K]

Assuming ya meant $\frac{csc(-x)}{1+tan^2(x)}$

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos

for the pythaogreaon identity
$cos^2(x)+sin^2(x)=1$
divide both sides by $cos^2(x)$
$1+tan^2(x)=sec^2(x)$ since $\frac{sin(x)}{cos(x)}=tan(x)$
subsitute
$\frac{csc(x)}{sec^2(x)}$

recall that $csc(x)=\frac{1}{cos(x)}$
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore $csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)$
so we get

$\frac{csc(x)}{sec^2(x)}$
decompose them into $\frac{1}{cos(x)}$ and $\frac{1}{sin^2(x)}$ to get $\frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}$
multiply by $\frac{sin^2(x)}{sin^2(x)}$ to get
$\frac{sin^2(x)}{cos(x)}$
we can furthur simlify to get
$(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)$
the expression simplifies to tan(x)sin(x)

5 0

3 years ago

Read 2 more answers