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grin007 [14]
2 years ago
11

PLS HELP!?!?!!??!?!?!?

Mathematics
1 answer:
Nutka1998 [239]2 years ago
3 0

Answer:

What is ej fekfe

Step-by-step explanation:

im finally taken

im not single

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You have just opened a new nightclub, Russ' Techno Pitstop, but are unsure of how high to set the cover charge (entrance fee). O
Neko [114]

Answer:

a)q(p)=-15p+ +300

b)R(p)=-15p²+300p

c)C(p)=-30p+1600

d.1)P(p)=-15p²+330p-1600

d.2)p=$11

Step-by-step explanation:

(a).Before getting started, we are going to consider  the cartesian plane, where x-axis corresponds to the cover charge and y-axis corresponds to number of guests per night . There, we will locate the following coordinates according to the previous information:

(9,165)  (10,150).

Remember that  the slope-intercept form of the  linear equation is y=mx+b where m is the slope and b  is te intercept.

The slope can be calculated  by the next formula:

m=\frac{y2-y1}{x2-x1}

In this case we will assign  (9,165) as the first coordinate and (10,150) as the second one. The order does not matter. At the end we get the same value for m.

Therefore:

m=\frac{150-165}{10-9} = -15

Now, we have the slope and two poitns. According to this, and taking into account that  point-slope form of the equation of a line is y-y1=m(x-x1),   find a linear demand equation.

Any of two coordintates can be selected. In this case we will select the second one.

y-150=-15(x-10)   equation 1

Solve equation 1 for y

y=-15x+150+150

y=-15x+300

Above we had defined x as cover charge (p) and y as number of guests (q). Thus, rewrite equation 1.

q(p)=-15p+ +300.  

it equation shows the number of guests per night as a function of the cover charge,

(b). The nightly revenue can be calculated multplying the price of the cover charge by  the number of guests. So, we just have to multiply the equation 1 by p.

p*q(p)=p*(-15p +300)

R(p)=-15p²+300p   equation 2

(c) To get the cost function of the nightclub  we just have to multiply the cost of the two non-alcoholic drinks   by the number of the guests ( equation 1) and add to it  nightly overheads.

C(p)=2*(-15p+300)+1000

C(p)= -30p+600+1000

C(p)=-30p+1600  equation 3

(d) In order to find the profit in terms of the cover charge we will  subtract nightly costs ( equation 3) from nightly revenue (equation 2)

P(p)=R(p)-C(p)

P(p)=-15p²+300p - (-30p+1600)

P(p)=-15p²+300p+30p-1600

P(p)=-15p²+330p-1600

To determine that  the entrance fee we should charge for a maximum profit we are going to use the first derivative test (y'(x)=0) in order to find an extremum point.

Compute the first derivative of P(p)

P'(p)=-30p+330=0

30p=330

p=330/30

p= $11

The entrance fee that we should charge for a maximum profit is p=$11 per guest.

5 0
3 years ago
What is the graph of 3x + 5y = –15? Image for option 1 Image for option 2 Image for option 3 Image for option 4
saveliy_v [14]
Move x
5y = - 15 - 3x
y = - 3 - 3/5x
y = - 3/5 - 3
-y = 3/5 + 3
6 0
3 years ago
PLZ HELP :)<br> here's the problem !​
Pavlova-9 [17]

Answer: I think the answer is 34.. sorry if I’m wrong

Step-by-step explanation:

3 0
3 years ago
Maxwell is taking out a loan for $8,750 for 2 years at an APR of 9.75%. What would be the finance charge to the nearest whole do
Sladkaya [172]

Answer:

Step-by-step explanation:

Using the formula for calculating simple interest

SI = principal × rate × time/100

Given

Principal = $8750

Rate = 9.75%

Time = 2years

Substitute

Interest = 8750×9.75×2/100

Interest = 87.59×19.5

Interest = 1,706.25

Hence the finance charge to the nearest whole dollar is $1706

8 0
3 years ago
How do I complete the division problem
lisabon 2012 [21]

Answer:

a= -5

b= 1

c= -5

d= -12

That should help

4 0
3 years ago
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