Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
-4 < n ≤ 5
Step-by-step explanation:
Since the left inequality is an open circle and going to the right, the sign will be >
Since the right inequality sign is a closed circle and is going left, the sign would be ≤
The open circle ends at -4 so, n > -4
The closed circle ends at 5 so, n ≤ 5
You combine them and it looks like this:
-4 < n ≤ 5
9x+12=5x+4
9x-5x=12-4
4x=8
x=8/4
x=2
Answer: The numbers are 10 and 23
Step-by-step explanation:
Let the smaller number be x
And the larger number be y
Ist sentence;
1. The sum of two numbers is 33.
X + y= 33 .........eqn 1
2. second sentence
the larger number is 3 more than two times the smaller number.
Y = 3 +2x
Put y into eqn 1
X+ 3 +2x = 33
3x= 33- 3
3x= 30
X = 30/3
X= 10 and y= 3+ 2x
Y= 3+ 2(10)
Y = 3+ 20
Y= 23
Therefore the two numbers are 10 and 23
