Answer:
Approximately 3.5 feet - Option B
Step-by-step explanation:
Imagine that you have this walkway around the garden, with dimensions 30 by 20 feet. This walkway has a difference of x feet between it's length, and say the dimension 30 feet. In fact it has a difference of x along both dimensions - on either ends. Therefore, the increases length and width should be 30 + 2x, and 20 + 2x, which is with respect to an increases area of 1,000 square feet.
( 30 + 2x ) 
( 20 + 2x ) = 1000 - Expand "( 30 + 2x ) ( 20 + 2x )"
600 + 100x + 4
= 1000 - Subtract 1000 on either side, making on side = 0
4 + 100x - 400 = 0 - Take the "quadratic equation formula"
( Quadratic Equation is as follows ) - 
,
,
There can't be a negative width of the walkway, hence our solution should be ( in exact terms ) 
. The approximated value however is 3.5081...or approximately 3.5 feet.
Step-by-step explanation:
3.) A *the first one*
4.) C *the last one*
Answer: They are similar but not congruent.
Step-by-step explanation: hope this help
Answer:
r = i + j + (-2/3)(3i - j)
Step-by-step explanation:
Vector Equation of a line - r = a + kb ; where r is the resultant vector of adding vector a and vector b and k is a constant
if a = i + j ; b = t(3i - j) and r = -i +s(j)
for this to be true all the vector components must be equal
summing i 's
i + 3ti = -i; then t = -2/3
j - tj = sj; then s = 1-t; substitue t; s=1+2/3 = 5/3
so r = i + j + (-2/3)(3i - j) which will symplify to -i + 5/3j
