What happens to the value of the expression 3 y over 2 y as y increases
1 answer:
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Answer:
1) Real and same.
2) Real and distinct
3) Real and distinct
4) Real and distinct
5) Real and distinct
6) Real and distinct
7) Real and distinct
8) Real and distinct
Step-by-step explanation:
If a quadratic equation is in the form of ax² + bx + c = 0, then Discriminant of the equation D = b² - 4ac, which governs the nature of roots the equation has.
If D > 0, then there will be two different real roots.
If D = 0, then two same and real roots.
If D < 0, then two distinct but imaginary roots.
Now, 1) x² + 6x + 9 = 0 has D = 6² - 4 × 9 × 1 = 0. So, there will be two same and real roots.
2) 5x² - x = 4x² + 2
⇒ x² - x - 2 = 0
It has D = (-1)² - 4 × 1 × (-2) = 9. Therefore, the roots will be two distinct and real.
3)
⇒ 5 = x² - 4x
⇒ x² - 4x - 5 = 0.
So, D = (-4)² - 4 × (1) × (- 5) = 36. So, the equation has two real and distinct rools.
4) x(x - 5) = 4(5 - x)
⇒ x² - x - 20 = 0
Hence, D = (-1)² - 4 × 1 × (-20) = 81
So, the roots will be real and distinct.
5) x² + 7x + 1 = 0 has D = 7² - 4 × 1 × 1 = 45
So, the roots will be real and distinct.
6) 2x² + 9x + 3 = 0, has D = 9² - 4 × 2 × 3 = 57.
Hence, the roots will be real and distinct.
7) 5x² - 6 = 13x
⇒ 5x² - 13x - 6 = 0
So, D = (-13)² - 4 × 5 × (-6) = 289
So, the roots will be real and distinct.
8) x² - x = 3(x + 7)
⇒ x² - 4x - 21 = 0
It has D = (-4)² - 4 × 1 × (-21) = 100
So, the roots will be real and distinct. (Answer)
Answer:
System of linear equations
a: adult ticket price and c: child ticket price
Step-by-step explanation:
This system of equations can be used to find the price of the adult and child tickets.
We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).
Let a: adult ticket price and c: child ticket price,
we have for the first day that 3 adult tickets and 1 child ticket adds $38:
and for the second day we have that 2 adult tickets and 2 child tickets adds $52:
If we write this as a system of equations, we have:
Answer:
(1,1)
Step-by-step explanation:
we have
----> equation A
----> equation B
we know that
The solution of the system of equations is the intersection point both graphs
The intersection point both graphs is the point (1,1)
see the given graph
therefore
The solution is the point (1,1)
Remember that
if a ordered pair is a solution of a system of equations then the ordered pair must satisfy both equations of the system
<u><em>Verify</em></u>
Substitute the value of x=1 and y=1 in each equation and analyze the result
<em>Equation A</em>
---> is true
so
The ordered pair satisfy the equation A
<em>Equation B</em>
---> is true
so
The ordered pair satisfy the equation B
therefore
The ordered pair (1,1) is a solution of the system because satisfy both equations