The density of a block of cheese is 8 g/cm3. If the mass of the block is 260 g, the width of

An identification code is to consist of 3 letters followed by 2 digits. Determine the following

kirill [66]

Well let's see:

The first letter can be any one of 26 .
   For each one . . .
The second letter can be any one of the remaining 25.
   For each one . . .
The third letter can be any one of the remaining 24.
   For each one . . .
The two digits can be any number from 01 to 98 ...
   except 11, 22, 33, 44, 55, 66, 77, or 88. (No repetition.)
There are 90 of them.

So the total number of possibilities is (26 · 25 · 24 · 90) .

When I multiply that out, I get 1,404,000 .

I don't know how you got your number, so I can't comment on your
method, but I did find something interesting about your number:

If I assume that you did the three letters the same way I did, then
if I divide your number by (26·25·24), the quotient will show me
how you handled the two digits.

   1,263,600 / (26·25·24) = 81 .

That's very intriguing, because it's so close to the 90 sets of digits
that I used. But I don't know what it means, or if it means anything
at all.

7 0

3 years ago

Read 2 more answers

What's the verbal expression for 100-5n

Yuri [45]

Five times a number less than one hundred.

6 0

2 years ago

Read 2 more answers

When evaluating, what will be the exponent of 10 in the quotient?<br> 3<br> 4<br> 8<br> 16

qaws [65]

In this case it would be 8

3 0

2 years ago

Read 2 more answers

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

So

$P(X >300 ) = 0.97219$

8 0

3 years ago

Each angle of a regular pentagon has a measure of

Andrew [12]

Answer:

congruent

Step-by-step explanation:

All sides are the same length (congruent) and all interior angles are the same size (congruent). To find the measure of the interior angles, we know that the sum of all the angles is 540 degrees (from above)... And there are five angles... So, the measure of the interior angle of a regular pentagon is 108 degrees.

6 0

3 years ago