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2 years ago

10

It takes Daisy 2 hours to complete her homework from school. how long does it take Daisy to complete her homework in min ______

? MIN
WILL GIVE BRAINLIEST

2 answers:

padilas [110]2 years ago

6 0

1 hour is 60 minutes

2 hours is 60 minutes x 2

Therefore: 120mins to complete her homework

maksim [4K]2 years ago

4 0

Answer:

120 minutes

Step-by-step explanation:

1 hour = 60 min

2x = answer

x = 60

2 (60) = 120

Answer = 120 minutes

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Step-by-step explanation:

y - 1 = 2(x + 2)

y - 1 = 2x + 4

y = 2x + 5

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3 years ago

Help me and I’ll thank you

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John collected 17 leaves to feed his caterpillar collection if he wanted to split the leaves equally amongst the four cages how

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It lies between the numbers 4 and 5

Step-by-step explanation:

If John has 17 leaves and 4 cages then he should put 17/4, or 16/4+1/4 which is 4+0.25, or 4.25 in each cage.

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3 years ago

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In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

THIS IS 100 POINTS SOMEBODY PLEASEEEEEEEEEEEEEE HELP MEEEEE

Nookie1986 [14]

Answer: Option #4: the 0.2 could be changed to 2.

Explanation:

The table is designed to make the concept of percentages more understandable. The table first allocates the total amount of 70 in terms of its "fifths," or 20% parts. Then it expresses these parts in the last row of the table, showing that 20% of 70 is 14 and all the five parts sum up to 70 again.

Now, Mikel is supposed to express 40% of the amount. So she writes (incorrectly): 0.2 * 14. This statement needs to be changed to 2 * 14 (two times 14 = 28), to correspond to 2 times 20%, or 40% of 70.

This is reflected in the last (fourth) option "The 0.2 in the expression could be changed to 2."

Option #3 is incorrect because changing 14 to 70, will result in an incorrect number (2.8).

Options 1 and 2 are similarly incorrect (as can be easily verified)

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3 years ago

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