Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.
Thus, the length of fencing needed is given by
P = x + 2y
The area of the rectangle is given by xy,
i.e.

Substituting for y into the equation for the length of fencing needed, we have

For the amount of fencing to be minimum, then

Now, recall that

Thus, the length of fencing needed is given by
P = x + 2y = 24 + 2(12) = 24 + 24 = 48.
Therefore, 48 feets of fencing is needed to enclose the garden.
<span>precision is after the decimal point.
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1/8 is the answer to the problem
If the original side length is "s" and the original slant height is "h", the original surface area is
.. S = (base area) +(lateral area)
.. S = s² +(1/2)*(4s)*h
.. S = s(s +2h)
Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have
.. S' = (3s)(3s +2h/5)
.. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)
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Of course, in terms of the modified dimensions, the formula is the same:
.. S' = s'(s' +2h')
Answer: your wuestion isn’t specific enough.
Step-by-step explanation: