Question

Determine the zeros of the quadratic function f(x) = (x + 6)^2 – 9

Answer 1

${ \huge{ \underline{ \rm{Given}}}}$

${ \large{ \sf{f(x) = (x + 6) {}^{2} - 9 = 0}}}$

${ \large{ \bf{ \underline{Formula = { \underline{a {}^{2} - b {}^{2} = (a + b)(a - b)}}}}}}$

${ \large{ \sf{(x + 6) {}^{2} - (3) {}^{2} = 0}}}$

${ \large{ \sf{(x + 6 + 3)(x + 6 - 3) = 0}}}$

${ \large{ \sf{(x + 9)(x - 3) = 0}}}$

${ \large{ \therefore{ \sf{Zeros = x ={ \boxed{ \sf( - 9 \: \: and \: - 3)}}} \: \: Ans.}}}$

Answer 2

-9 and -3

i hope this helps