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34kurt
3 years ago
7

Graph the function f(x)=x^3-2x+7

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

The graph is down below and if that helps u out pls mark me as brainliest:)

Step-by-step explanation:

~Alex

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Find the center and the radius of the circle given this equation:<br> 2<br> x + 4x + y ² -10y +20=0
NemiM [27]

Answer:

vertex: (5/6,5)

focus: (- 2/3, 5)

axis of symmetry: y = 5

directrix: x = 7/3

Step-by-step explanation:

use the vertex form to determine the values of a.h. and k and use these values to find the direction the parabola opnes, vertex, foucs, axis of symmetry, and directrix

5 0
3 years ago
Domingo works 40 hours per week as a tire store manager . If he made $29640 last year. how much he made per hour
Fed [463]
THERE ARE 52 WEEKS IN A YEAR.
40 (hours) x 52 (weeks) = 2080
29460 / 2080 = 14.25

He made a. $14.25 per hour.
5 0
3 years ago
20+20=? giving 20 pts
Ad libitum [116K]

Answer:

40

Step-by-step explanation:

20 + 20 = 40

That is literally all there is to it

7 0
3 years ago
In how many ways can 4 different contracts be distributed among 12 different firms, if no two contracts are awarded to the same
vagabundo [1.1K]

The first contract can go to any of 12 firms. The second can go to any of the remaining 11 firms, and so on. Finally, the 4th contract can go to any of the 9 firms that don't yet have a contract.

The number of ways the contracts can be awarded is

... 12×11×10×9 = 11,880

5 0
4 years ago
6) If sec theta+tan theta = P. PT sin theta=P^2-1/P^2+1 ...?
jarptica [38.1K]
I will use the letter x instead of theta.

Then the problem is, given sec(x) + tan(x) = P, show that

sin(x) = [P^2 - 1] / [P^2 + 1]

I am going to take a non regular path.

First, develop a little the left side of the first equation:

sec(x) + tan(x) = 1 / cos(x) +  sin(x) / cos(x) = [1 + sin(x)] / cos(x)

and that is equal to P.

Second, develop the rigth side of the second equation:

[p^2 - 1] / [p^2 + 1] =

= [ { [1 + sin(x)] / cos(x) }^2 - 1] / [ { [1 + sin(x)] / cos(x)}^2 +1 ] =

=  { [1 + sin(x)]^2 - [cos(x)]^2 } / { [1 + sin(x)]^2 + [cos(x)]^2 } =

= {1 + 2sin(x) + [sin(x)^2] - [cos(x)^2] } / {1 + 2sin(x) + [sin(x)^2] + [cos(x)^2] }

= {2sin(x) + [sin(x)]^2 + [sin(x)]^2 } / { 1 + 2 sin(x) + 1} =

= {2sin(x) + 2 [sin(x)]^2 } / {2 + 2sin(x)} = {2sin(x) ( 1 + sin(x)} / {2(1+sin(x)} =

= sin(x)

Then, working with the first equation, we have proved that [p^2 - 1] / [p^2 + 1] = sin(x), the second equation.


4 0
4 years ago
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