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Sever21 [200]
2 years ago
11

Someone help me :-):-):-) no flile ​

Mathematics
1 answer:
egoroff_w [7]2 years ago
4 0

Answer: 2x+8 and 2(x+4)

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Well u first have to eat a subway italian but it's is bomb
8 0
3 years ago
Please help me with this math problem I don’t know it I need to pass this class !!!!!!
Alisiya [41]

The correct option is Option 4: 2a^2b^3 + 10ab^4

Step-by-step explanation:

Given

Length of box = l = ab

Width of box = w = a+5b

Height of box = h = 2b^2

The volume of a box is given by:

V = Length*Width*Height\\V = l*w*h

Putting the values

V = (ab)(a+5b)(2b^2)\\ = (ab)(2b^2)(a+5b)\\=(2ab^3)(a+5b)\\Distributive property\\=(2ab^3*a) + (2ab^3*5b)\\=2a^2b^3 + 10ab^4

Hence,

The correct option is Option 4: 2a^2b^3 + 10ab^4

Keywords: Volume, Polynomials

Learn more about polynomials at:

  • brainly.com/question/9103248
  • brainly.com/question/9323337

#LearnwithBrainly

4 0
3 years ago
What is the LCM and GCF of 13 and 15?!
AlladinOne [14]
LCM\\\\
13:13\\1:1\\\\
15:3\\
5:5\\1:1\\\\LCM(13,15)=1*3*5*13=195\\\\
GCF:\\\\GCF(13,15)=1.
3 0
3 years ago
Read 2 more answers
100%
julsineya [31]

Answer:

55/200 in percentage is 27.5 percent

So answer is 27.5

3 0
3 years ago
Can you please answer this question
tamaranim1 [39]
3tan^{2} \theta +7sec\theta=3
First I converted the equation terms into sine and cosine.
tan^{2}\theta = \frac{sin^{2}\theta}{cos^{2}\theta} and sec\theta= \frac{1}{cos\theta}
Substitution:
\frac{3sin^2\theta}{cos^2\theta} + \frac{7}{cos\theta} =3
Common Denominator Created:
\frac{3sin^2\theta}{cos^2\theta} + \frac{7cos\theta}{cos^2\theta} =3
Multiply each term by the LCD:
3sin^2\theta+7cos\theta=3cos^2\theta
Substitution: Recall ⇒sin^2\theta =1-cos^2\theta 
3(1-cos^2\theta)+7cos\theta=3cos^2\theta
Distribute and collect all terms on one side:
6cos^2\theta-7cos\theta-3=0
Factor and set each factor equal to 0:
(2cos\theta-3)(3cos\theta+1)=0
2cos\theta-3=0⇒theta=cos^{-1} \frac{3}{2}
3cos\theta+1=0⇒theta=cos^{-1} \frac{-1}{3}
The 2nd factor provides only possible answer 109.5 degrees

4 0
3 years ago
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