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kow [346]
3 years ago
9

The amounts of money Gillian earned each week from babysitting are $5, 10, $20, $10, $15, $5, $42, $5. How is the mean of the da

ta set affected when the outlier is removed?
Mathematics
1 answer:
Solnce55 [7]3 years ago
5 0

Answer:

The mean will increase, after the outlier is removed.

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Write each absolute value in a box to show the order from least to greatest.
arsen [322]

Answer:

|–2| |5| |–8| |11| |–12|

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3 years ago
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Browns department store is having a 1/4 off sale. How much would a shirt that regularly sells for 36.00 cost during the sale?
nadya68 [22]
Since the shirt is 25 percent off your paying for 75 percent of the shirt. 0.75(36) is 27. The shirt will cost 27.00
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3 years ago
Which of the sums below can be expressed as 6(3 + 9)?<br> 18 + 54<br> 18 +9<br> 09 + 15<br> 6 + 54
Zinaida [17]

Answer: 18+54

Step-by-step explanation:

6*3=18 and 6*9=54

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3 years ago
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ABCD is a rectangle and AC and BD are its diagonals. If AC = 10 cm, then BD is?
kiruha [24]

Answer:

A. 10 cm

Step-by-step explanation:

In a right angled triangle, a² + b² = c² where c is the diagonal or hypotenuse. If you split a rectangle diagonally into two right angle triangles, the a and b of both triangles would be the same length. Therefore, the c or diagonals would also be the same length - 10 cm.

Hope this helps!

5 0
3 years ago
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Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

#SPJ1

7 0
2 years ago
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