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Naya [18.7K]
3 years ago
10

Evaluate the piecewise function at the given values of the independent variable.

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0
Hsbss s shsbdbshe shejsbshehd sbsjsbshs s shsjsbs
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The variables x and y vary inversely If x=5 when y=12, then find the value of x when y=32
Vilka [71]

Answer:

x=15/8

Step-by-step explanation:

Inverse variation is given by

xy = k

Substituting x=5 and y=12

5*12 = k

60 =k

Our original equation is xy = 60

Now let y=32

x*32 = 60

Divide each side by 32

32x/32 = 60/32

Divide top and bottom by 4

x = 15/8

4 0
4 years ago
What is the answer to 5x-2=8
sergejj [24]
I hope this helps you



5x=8+2


5x=10


5x÷5=10÷5


x=2
4 0
4 years ago
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X2 + 4x - 21 = 0 quadratic formula
Elena-2011 [213]

Answer:

0

Step-by-step explanation:

x2 +4x-21=0. solve for x

x =  \frac{7}{2}

x = 3 \frac{1}{2}  \ x = 3.5

6 0
3 years ago
How is a one-degree angle helpful in classifying angles?
Oksana_A [137]
It is helpful by knowing it has at least one acute angle
4 0
3 years ago
Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3. What is the volume of the
Arisa [49]
:<span>  </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)). 

There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned. 

Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".

Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s. 

Plugging in t = 169 gives 2/13 cm3/s.</span>
4 0
3 years ago
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