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gtnhenbr [62]
3 years ago
11

Because of hiring a plumber, y, to work x hours on a repair project can be modeled using a linear function. the plumber charges

a fixed cost of $80 plus an additional cost of $45 per hour. the plumber works a maximum of 8 hours per day
Mathematics
1 answer:
seraphim [82]3 years ago
4 0

Answer:

The plumbers cost would be equal to the equation 80+45x=y with y being the total amount of money he made and x being how many hours he worked.

Step-by-step explanation:

In this equation to find the amount the plumber was paid all you need to do is plug in the amount of hours he worked for x.

If the plumber worked his maximum of 8 hours then the equation would change from 80+45x=y to 80+(45×8)=440.

So, if the plumber worked for 8 hours he would make $440.

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What is the volume of a sphere that has a radius of 18ft​
mihalych1998 [28]

Answer:

24432.193

Step-by-step explanation:

Volume of sphere = 4/3 pi x cube of radius

Radius =18ft , pi = 3.142

Volume = 4/3 x 3.142 x 18 x 18 x 18

Volume = 1.3333 x 3.142 x  5832

Volume = 24432.19ft3

Volume =24432ft3 to the nearest whole number

I hope this was helpful, Please mark as brainliest

5 0
3 years ago
Help with this??? please
Aleks [24]
Look at the picture.

Use the Pythagorean theorem.

(19+r)^2=r^2+35^2\\\\19^2+2\cdot19\cdot r+r^2=r^2+1225\ \ \ |-r^2\\\\361+38r=1225\ \ \ |-361\\\\38r=864\ \ \ |:38\\\\r\approx22.737

The diameter d = 2r.

Therefore

d=2\cdot22.737=45.474\approx45.5

Answer: 45.5

4 0
3 years ago
What are the exact values of sin theta cos theta tan theta if (3,-4) is a point on the terminal side of theta?
malfutka [58]
\bf (\stackrel{a}{3}~,~\stackrel{b}{-4})\impliedby \textit{now let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{3^2+(-4)^2}\implies c=\sqrt{25}\implies \boxed{c=5}

\bf -------------------------------\\\\
sin(\theta )=\cfrac{\stackrel{opposite}{-4}}{\stackrel{hypotenuse}{5}}\qquad cos(\theta )=\cfrac{\stackrel{adjacent}{3}}{\stackrel{hypotenuse}{5}}\qquad tan(\theta )=\cfrac{\stackrel{opposite}{-4}}{\stackrel{adjacent}{3}}
6 0
3 years ago
5x - 2 = 8 + 5y<br> Solve for y and show work.
solniwko [45]
The answer is “x=y+2” hopefully this helps :)))))

7 0
3 years ago
Write an equation in slope-intercept form of the line with the parametric equations x=2t and y=1-t
pentagon [3]

Answer: -x/2 + 1

Step-by-step explanation:

write t in terms of x

x = 2t

t = x/2

substitute t in y

y = 1 - t

y = 1 - x/2 or -x/2 + 1

6 0
3 years ago
Read 2 more answers
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