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3 years ago

13

PLSSSS HELPPPPPPP ONCE AGAIN LAST CHANCE MATHHH PLSSSSS HELPPPPP ASAPPPP AND PLEASE OH PLEASE GIVE ME RIGHT ANSWERS NOT ABBSURB

ONES I NEED THIS!!!! WILL REWARD BRAINLIEST TO RIGHT AND GOOD ANWSERS!!!!!!!!!!!

1 answer:

Serggg [28]3 years ago

6 0

Answer:

Question 1: B

Question 2: D

Question 3: D

Step-by-step explanation:

$2x^{2}$ +4x-3x-6

group and simplify

(2x-3)(x+2)

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What is the equation of the line that is perpendicular to y= -3x + 1 and passes through (2,3)?

Aleonysh [2.5K]

Answer:

$\large\boxed{y=\dfrac{1}{3}x+2\dfrac{1}{3}}$

Step-by-step explanation:

$\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=-3x+1\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The equation of the searched line:}\ y=\dfrac{1}{3}x+b.\\\\\text{The line passes through }(2,\ 3).$

$\text{Put the coordinates of the point to the equation.}\ x=2,\ y=3:\\\\3=\dfrac{1}{3}(2)+b\\\\3=\dfrac{2}{3}+b\qquad\text{subtract}\ \dfrac{2}{3}\ \text{from both sides}\\\\b=2\dfrac{1}{3}$

3 0

3 years ago

Read 2 more answers

Can some solve me this one question

iogann1982 [59]

What is the question?

7 0

3 years ago

Please help. I’ll mark you as brainliest if correct!

chubhunter [2.5K]

Answer:

$\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }$

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is $[1;+\infty[$

$f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2$

x>=1 so x is positive and we can take the square root

so $f^{-1}(x)=1+\sqrt{x}$

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3 years ago

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blagie [28]

Answer:

2 = x- coordinate

3 = y coordinate

Step-by-step explanation:

REMEMBER: In an ordered pair, the x-coordinate always comes first.

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3 years ago

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scZoUnD [109]

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