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eimsori [14]
3 years ago
11

What is 22 + 125 - 6

Mathematics
2 answers:
Flauer [41]3 years ago
7 0

Answer:

141

Step-by-step explanation:

22+125=147

147-6=141

therefore

the answer is 141

uysha [10]3 years ago
4 0

Answer:

141

Step-by-step explanation:

calculator

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Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
4 years ago
What is an equation of the line that passes through the points (-6,5) and (6,7)
Andrei [34K]

Answer:

y = 1/6 x + 6

Step-by-step explanation:

m = (y2-y1)/(x2-x1)

m = (7-5)/(6-(-6))

m = 2/12 = 1/6

Substitute x and y values with a pair of coordinates,

y = mx+c

7 = 1/6(6) + c

7 = 1 + c

c = 6

Thus, the equation is y = 1/6 x +6

8 0
3 years ago
If that value of x in the above diagram equals 26
jeyben [28]

Please put the picture so I can answer the question

6 0
3 years ago
Write an equation for each problem. Then solve.
Nana76 [90]

Answer:

<em>The price is the same at both stores for 2 prints.</em>

Step-by-step explanation:

<u>Equations</u>

Let's set the variable

x = number of photo prints

Company Photo Plus charges $2 for each print and $6 for a processing fee, thus the total charges are:

PP = 6 + 2x

Company Picture Time charges $3 for each print and $4 for a processing fee, thus it charges a total of:

PT = 4 + 3x

It's required to find the number of prints that make both stores charge the same. Equating both functions:

6 + 2x = 4 + 3x

Subtracting 2x and 4:

x = 2

The price is the same at both stores for 2 prints.

4 0
3 years ago
A marine surveyor uses a rangefinder and a compass to locate a ship and an island in the vicinity of the coast on which she stan
Lemur [1.5K]

Answer:

The distance between the ship and the island is d\approx 567.23 \ft.

Step-by-step explanation:

The ship's azimuth is the direction measured as an angle from the north.

You should draw a diagram of the situation.

From the information given we know two distances and the angle between them and we want to find the distance between the ship and the island.

To find the distance between the ship and the island we can use the Law of Cosines.

<em>If a, b and c are the lengths of the legs of a triangle opposite to the angles A, B and C respectively; then the law of cosines states:</em>

c^2=a^2+b^2-2ab\cdot cos(C)

This law is useful for finding: the third side of a triangle when we know two sides and the angle between them like in this case.

The angle is

\theta=48\°+(360-332)\°=76\°

And the distance is given by

d=\sqrt{393^2+515^2-2(393)(515)cos(76)} \\\\d=\sqrt{-404790\cos \left(76^{\circ \:}\right)+419674}\\\\d\approx 567.23 \ft.

7 0
3 years ago
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