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3 years ago

HELP ME!!!!! I really need the answer to this!!!!!!!

Mathematics

2 answers:

larisa86 [58]3 years ago

5 0

Answer:

12x^8y^8

Step-by-step explanation:

taking numbers in one side and multiplying and taking the variables in other sides and adding the power

charle [14.2K]3 years ago

5 0

-12x^8y^7 this is the answer

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Andre and Diego were each trying to solve 2+6=3−8. Describe the first step they each make to the equation.The result of Diego’s

Fiesta28 [93]

Step-by-step explanation:

2+6=3-8

2+6=8

3-8=-5

8=-5

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3 years ago

Gianna is going to throw a ball from the top floor of her middle school. When she throws the ball from 48feet above the ground,

My name is Ann [436]

Answer: t = 3seconds

Step-by-step explanation:

To find the zero means we will equate the function to zero and then solve, that is

$-16t^{2}$ + 32t + 48 = 0

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(t+1)(-16t+48) = 0

Therefore:

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3 years ago

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Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

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3 years ago

Someone please help what’s 9+10?

Digiron [165]

Answer:

Hey There!

$\huge\colorbox{yellow}{Myself \: someone}$

$9 + 10 = 19$

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3 years ago

In how many minutes will a heart beat in 140 times?

matrenka [14]

The answer is 5 minutes

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3 years ago

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