Sulphur is located in the third period and group 16. The general electronic configuration of group 16 is therefore the maximum number of valency electrons in group 16 is 6. The electronic configuration of sulphur is [Ne]
. Sulphur has six valency electrons whereas sulphur can have more than eight electrons in its valency shell as it have an empty d-shell electrons can accumulate in the empty d-shell. The complete d-shell and the
orbital will be empty. As each orbital can accept 2 electrons, sulphur can have 12 valency electrons in its valency shell.
why does ch3coch3 has stronger intermolecular forces than c2h5oc2h5? even though both have dipole-dipole as their IMF, but c2h5o
c2h5 has a larger molecular weight and as the molecular weight increases, the IMF get stronger. so why it is the opposite here?
1 answer:
I think because the CH3COCH3(second picture) has a ketone(the double bond to oxygen C=O) in the chemical structure and I believe ketones lead to stronger IMF than ethers(C-O-C). I am not sure about this, but I hope this answer will at least help give you a hint as to what to look up to figure this out. I'm sorry I couldn't be of more help!
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<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 119.89 grams
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of NaI solution = 0.130 M
Volume of solution = 0.400 L
Putting values in above equation, we get:
The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:
The precipitate (insoluble salt) formed is lead (II) iodide
By Stoichiometry of the reaction:
2 moles of NaI produces 1 mole of lead (II) iodide
So, 0.52 moles of NaI will produce = of lead (II) iodide
To calculate the number of moles, we use the equation:
Moles of lead (II) iodide = 0.26 moles
Molar mass of lead (II) iodide = 461.1 g/mol
Putting values in above equation, we get:
Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams