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SashulF [63]
4 years ago
15

Write the equilibrium constant expression, Kc, for the following reaction: If either the numerator or denominator is 1, please e

nter 1 CaCO3(s) Ca2+(aq) + CO32-(aq)
Chemistry
1 answer:
yanalaym [24]4 years ago
5 0

Answer:

Explanation:

THE QUESTION SHOULD BE

Write the equilibrium constant expression, Kc, for the following reaction: If either the numerator or denominator is 1, please enter 1 CaCO3(s).

CaCO3(s) <=> Ca2+(aq) + CO32-(aq)

Write the mathematical form of the concentration of the products, then divide it by the concentration of the reactants as follows

Kc =[Ca2+]^1 . [CO32-]^1 / [CaCO3]^1

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An HCl solution has a concentration of 0.09714 M. Then 10.00 mL of this solution was then diluted to 250.00 mL in a volumetric f
aivan3 [116]

Answer:

a. 3.8856x10⁻³M HCl

b. 1.23x10⁻⁴M OH⁻

c. 1.23x10⁻⁴M Ag⁺

d. Ksp = [Ag⁺] [OH⁻]

Explanation:

a. The reaction that you are studying is:

HCl(aq) + AgOH(aq) → H₂O(l) + AgCl(s)

The HCl solution is diluted from 10.00mL to 250.00mL, that is:

250.00mL / 10.00mL = <em>25 -The solution is diluted 25 times-</em>

As original concentration of HCl is 0.09714M, the concentration of the diluted solution is:

0.09714M / 25 =

<h3>3.8856x10⁻³M HCl</h3><h3 />

b. 1 mole of HCl reacts per mole of AgOH, moles of HCl that reacts are:

7.93mL = 7.93x10⁻³L × (3.8856x10⁻³mol HCl / L) = 3.0813x10⁻⁵ moles of HCl.

Based on the reaction, you have in solution

<em>3.0813x10⁻⁵ moles of AgOH = Ag⁺ = OH⁻</em>

The AgOH solution was 250.0mL = 0.2500L, its concentration is:

3.0813x10⁻⁵ moles OH⁻ / 0.2500L =

<h3>1.23x10⁻⁴M OH⁻</h3><h3 />

c. In solution, AgOH produce Ag⁺ and OH⁻ in equals proportions, that means:

1.23x10⁻⁴M OH⁻ =

<h3>1.23x10⁻⁴M Ag⁺</h3><h3 />

d. The solubility product reaction of AgOH(s) is:

AgOH(s) ⇄ Ag⁺(aq) + OH⁻(aq)

Where Ksp for this reaction is defined as:

<h3>Ksp = [Ag⁺] [OH⁻]</h3>
5 0
3 years ago
Is ammonia an alkali or base?​
Alchen [17]
Ammonia is a weak base because its nitrogen atom has an electron pair that readily accepts a proton.
6 0
3 years ago
How do fermentation reactions in oxygen-starved muscle cells and anaerobically grown yeast cells differ?
dedylja [7]

In oxygen- starved muscle cells in anaerobic respiration lactic acid is formed while in anaerobic respiration by yeast cells it produces ethanol and carbon dioxide.

Explanation:

Respiration occurring in absence of oxygen in muscles leads to accumulation of lactic acid and very less amount of energy. This is fermentation process as the end product formed is lactic acid.

The process of fermentation takes place in yeast bacteria and oxygen starved cells of muscles.

The yeast can ferment simple sugars like glucose and fructose into ethyl alcohol and carbon dioxide.

In general human respiration is aerobic but during strenuous exercise, oxygen does not meet the demand of working out muscle, so they respire anaerobically and produce lactic acid and 2 ATP i.e very less compared to 38 molecules of ATP in aerobic respiration.

8 0
3 years ago
you need 16.66ml (+-0.01) of 53.4 (+-0.4)wt% of NaOH with a density of 1.52 (+-0.01)g/mL to prepare 2.00L of 0.169M of NaOH. Wha
pashok25 [27]

Answer:

The absolute uncertainty is approximately 1.69 × 10⁻³

Explanation:

The volume needed for NaOH needed to make the solution = 16.66 ml

The wt% of the added NaOH = 53.4 wt%

The volume of the NaOH to be prepared = 2.00 L

The concentration of the NaOH to be prepared = 0.169 M

The molar mass of NaOH = 39.997 g/mol

Therefore, 100 g of sample contains 53.4 g of NaOH

The mass of the sample = 16.66 × 1.52 = 25.3232 g

The mass of NaOH in the sample = 0.534 × 25.3232 = 13.5225888 g ≈ 13.52 g

Therefore;

The number of moles of NaOH = 13.52/39.9971 = 0.3381 moles

Therefore, we have 0.3381 moles in 2.00L solution, which gives;

The number of moles per liter = 0.3881/2 = 0.169045 moles/liter

The molarity ≈ 0.169 M

The absolute uncertainty, u(c) is given as follows;

u(c) = \sqrt{ \left (\dfrac{0.01}{16.66} \right )^2 + \left ( \dfrac{0.4}{53.4} \right )^2 + \left ( \dfrac{0.01}{1.52} \right )^2 }   \times 0.169 \approx 1.69 \times 10^{-3}

The absolute uncertainty, u(c) ≈ 1.69 × 10⁻³.

3 0
3 years ago
25. Compare the compositions of binary ionic and binary molecular compounds. 26. Write the general chemical formula for an acid,
Murljashka [212]

Explanation:

25. Binary ionic compounds: They are known as the compounds which contains a cation formed from a metal and an anion formed from a non-metal or a polyatomic anion. For example : Barium sulfate

Ba : +2 ( metal of group II-A)

SO_4 : -2 ( sulfate)

These two ions combine to form a binary ionic compound having formula BaSO_4

Binary Molecular compounds: They are known as the compounds which contain two or more non-metals that are bonded covalently. In these compounds, no ions are present because the electrons are shared by the atoms. Examples are: PCl_3 : phosphorous trichloride

SO_2 : sulfur dioxide

26. The general chemical formula for an acid is HX where H is the hydrogen and X is the non-metal or polyatomic ions. Examples of acids are:

HF : Hydrofluoric acid

H_2SO_4 : Sulfuric acid

5 0
4 years ago
Read 2 more answers
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