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SashulF [63]
3 years ago
15

Write the equilibrium constant expression, Kc, for the following reaction: If either the numerator or denominator is 1, please e

nter 1 CaCO3(s) Ca2+(aq) + CO32-(aq)
Chemistry
1 answer:
yanalaym [24]3 years ago
5 0

Answer:

Explanation:

THE QUESTION SHOULD BE

Write the equilibrium constant expression, Kc, for the following reaction: If either the numerator or denominator is 1, please enter 1 CaCO3(s).

CaCO3(s) <=> Ca2+(aq) + CO32-(aq)

Write the mathematical form of the concentration of the products, then divide it by the concentration of the reactants as follows

Kc =[Ca2+]^1 . [CO32-]^1 / [CaCO3]^1

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Stels [109]

Use the concentration and rate data presented in the table below to answer the following questions about the hypothetical reaction:

A + 2B + 4C→ 2D + E


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3 0
3 years ago
The half-life of 131I is 8.021 days.What fraction of a sample of 131I remains after 24.063 days
Leno4ka [110]
24.063/8.021 = 3 half lives
(1/2)^3 =1/8 
5 0
3 years ago
If 20.0g of CO2 and 4.4g of CO2
Ksivusya [100]

The given question is incorrect. The correct question is as follows.

If 20.0 g of O_{2} and 4.4 g of CO_{2}  are placed in a 5.00 L container at 21^{o}C, what is  the pressure of this mixture of gases?

Explanation:

As we know that number of moles equal to the mass of substance divided by its molar mass.

Mathematically,   No. of moles = \frac{\text{mass}}{\text{molar mass}}

Hence, we will calculate the moles of oxygen as follows.

       No. of moles = \frac{\text{mass}}{\text{molar mass}}

     Moles of O_{2} = \frac{20.0 g}{32 g/mol}

                            = 0.625 moles

Now,   moles of CO_{2} = \frac{4.4 g}{44 g/mol}

                                      = 0.1 moles

Therefore, total number of moles present are as follows.

Total moles = moles of O_{2} + moles of CO_{2}

                    = 0.625 + 0.1

                    = 0.725 moles

And, total temperature  will be:

                    T = (21 + 273) K = 294 K

According to ideal gas equation,  

                         PV = nRT

Now, putting the given values into the above formula as follows.

                P = \frac{nRT}{V}

                   = \frac{0.725 mol \times 0.08206 Latm/mol K \times 294 K}{5.00 L}

                    = \frac{17.491089}{5} atm

                    = 3.498 atm

or,                = 3.50 atm (approx)

Therefore, we can conclude that the pressure of this mixture of gases is 3.50 atm.

4 0
3 years ago
Which of the following processes does our Sun and other stars in our galaxy use to create energy?
Usimov [2.4K]

Answer:

fusion reaction

The simple answer is that the sun, like all stars, is able to create energy because it is essentially a massive fusion reaction. Scientists believe that this began when a huge cloud of gas and particles (i.e. a nebula) collapsed under the force of its own gravity – which is known as Nebula Theory.

Explanation:

hope this helps

5 0
2 years ago
Help help help help! Kingdom
Brrunno [24]

Answer:

all 4 of the middle ones are part of the nucleus

3 0
2 years ago
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