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Lemur [1.5K]
3 years ago
9

The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. find the diameter of the base of the cylinder​

Mathematics
1 answer:
White raven [17]3 years ago
6 0

Answer:

2 cm

Step-by-step explanation:

h = 14 cm

Curved surface area of a right circular cylinder = 88 cm²

2πrh = 88

2 * \frac{22}{7}*r*14=88\\\\r = \frac{88*7}{2*22*14}\\\\ r =1 \\\\r = 1 cm

Diameter = 2 * r = 2 * 1 = 2  cm

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The difference between two numbers is 9 and the product of the numbers is 162. Find the two numbers
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Let the no be X and Y

acc to ques....

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substituting value from 1 in 2 we get;

x=9+y

[9+y][y] = 162

y^2+9y = 162

y^2 + 9y - 162=0

y^2 + 18y - 9y - 162=0

y[y+18] + 9[y+18]=0

[y+9][y+18}

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y= -18......................................4



case 1 :

y= -9

x = 9-9=0

case 2:

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7 0
3 years ago
Please help!!!!<br> I desperately need the correct answer I’ve been trying all day!
zysi [14]

Answer:14708

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Exponential Growth:\text{Exponential Growth:}

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x

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Plug in time for x:\text{Plug in time for x:}

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5 0
3 years ago
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What is the answer to this question?
timurjin [86]

Answer: Option 1

Step-by-step explanation:

See attached image

3 0
2 years ago
 what is perpendicular to y= 3x -9 and passes through the point (3,1)
GREYUIT [131]
(3,1) , \ \ y= 3x -9 \\ \\ The \ slope \ is :m _{1} =3 \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \ m _{1} \cdot m _{2} = -1 \\ \\3\cdot m_{2}=-1 \ \ /:3\\ \\ m_{2}=-\frac{1}{3}

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6 0
3 years ago
Paco solves the equation -3x-5=1
Levart [38]

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7 0
3 years ago
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