Answer:
Statistical sampling is drawing a set of observations randomly from a population distribution. ... By repeating the sampling operation a large number of times, perhaps 1000, we decrease the sampling error and increase the quality of the estimates.
Answer:

Step-by-step explanation:
Given sequence: 
Therefore,
General form of an arithmetic sequence: 
(where a is the first term and d is the common difference)
To find the common difference, subtract a term from the next term:

Therefore,

To find the 6th term, input n = 6 into the equation:

The answer is 2:1 because at first your ratio would be 18:9 but if you divide that by 9 (for simplifying purposes) than its 2:1
Answer:
11610
Step-by-step explanation:
First you do the top rectangle which the area for that is 144 which is 4 times 4 times 3 times 3.
Then you do the middle rectangle which the area is 441 which is 7 times 7 times 3 times 3.
Then you do the last rectangle which the area is 11025 which is 15 times 15 times 7 times 7.
Then lastly you add all three areas which is 144+441+11025=11610. So therefore, the answer is 11610.