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xxMikexx [17]
3 years ago
6

If a motorcycle, a car, and a big rig are all moving with a velocity of 100 km/h, which vehicle has the greatest momentum? A mot

orcycle and rider. A small car. A large 18 wheeler truck.
Physics
2 answers:
faltersainse [42]3 years ago
7 0

Answer: A large 18 wheeler truck.

Explanation: Momentum is the measure of the motion of an object found by multiplying the object’s mass and velocity. Momentum is directly proportional to the object's mass and also its velocity. So, the greater an object's mass or the greater its velocity, the greater its momentum. Therefore, since the truck is bigger, it has the greatest mass. This means that the truck the greatest momentum. Correct on Edg 2020.

PLEASE GIVE BRAINLIEST AND RATE MY ANSWER  :)

daser333 [38]3 years ago
4 0

Answer:

The big rig.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

In this scenario, a motorcycle, a car, and a big rig are all moving with a velocity of 100 km/h. Thus, the vehicle which has the greatest momentum is the big rig because its mass is intuitively or logically greater than that of the other vehicle.

Generally, momentum is directly proportional to the mass of a physical object or body.

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Lyrx [107]

Answer:

a) 1.22 s

b) 9.089 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-12}{-9.81}\\\Rightarrow t=1.22\ s

Time taken by the ball to reach the highest point is 1.22 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=12\times 1.22+\frac{1}{2}\times -9.81\times 1.22^2\\\Rightarrow s=7.339\ m

The maximum height the ball will reach above the ground is 1.75+7.339 = 9.089 m

8 0
3 years ago
Experiment 7 static equilibrium of a rigid body.
Anna007 [38]

The answer is yes. You know this because the table isn't moving or rotating.

5 0
3 years ago
A 1.0-kg object moving in a certain direction has a kinetic energy of 2.0 J. It hits a wall and comes back with half its origina
saw5 [17]

Lets calculate the initial speed of the block. We know that kinetic energy is given by:

K_0 =\dfrac{mv_0^2}{2}

Solving for v₀:

v_0 = \sqrt{ \dfrac{2K_0}{m}} =  \sqrt{ \dfrac{2(2\;J)}{1\;kg}} = 2\;m/s

If the speed after it hits a wall is half its original speed then:

v = v₀/2 = 2 m/s / 2 = 1 m/s

Then the kinetic energy at this point is:

K =\dfrac{mv^2}{2} = \dfrac{(1\;kg)(1\;m/s)^2}{2} = \dfrac{1}{2}\;J = 0.5\;J

The inetic energy of this object at this point is 0.5 J.

5 0
3 years ago
Which of the following does NOT describe the conversion of potential to kinetic energy?
ivann1987 [24]
I believe it would be A. (:
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5. Annie drags her little red wagon with a mass of 5.00 kg, up a hill that has an angle of
maxonik [38]

Answer: 25.08\ m/s^2

Explanation:

Given

mass of wagon m=5 kg

elevation

\theta =30.9^{\circ}\\F=150\ N

Sin component of weight will oppose the applied force therefore we can write

F-W\sin \theta=ma\\where\\W=weight(mg)\\a=acceleration

150-5\times 9.8\times \sin (30.09)^{\circ}=5\times a\\125.43=5a\\a=25.08\ m/s^2

6 0
3 years ago
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