Question

A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the ball? 20 N • s 37 N • s 41 N • s 78 N • s

Answer 1

Answer:

78 N s

Explanation:

The impulse exerted on the ball is given by:

$I = F \Delta t$

where

F is the magnitude of the force

$\Delta t$ is the duration of the collision

In this problem,

F = 39 N

$\Delta t = 2 s$

Substituting,

$I=(39 N)(2 s)= 78 Ns$