Answer:
Step-by-step explanation:
On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?
Let:
RM 30 = x
RM 50 = y
x + y = 800 - - - (1)
30x + 50y = 30000 - - - (2)
From (1)
x = 800 - y
Put x = 800 - y in (2)
30(800 - y) + 50y = 30000
24000 - 30y + 50y = 30000
24000 + 20y = 30000
20y = 30000 - 24000
20y = 6000
y =
Answer:
G. 7
Explanation:
The longest side must be less than the sum of the two shorter sides.
The difference between the longest and shortest sides must be less than the middle side.
l+a = 11
l < (a + 4) ... l < (11 - l + 4)
... 2 l < 15 ... l < 7.5
--Variables
l = 7 (Longest Side/Answer)
a = 4 (Other Missing Length)
m = 4 (Side Given)
So perimeter<u><</u>556
permiter=2Legnth+2Width
so perimiter=2(legnth+width)
556/2<u>></u>Legnth+width
228<u>></u>legnth +width
legnth =150
so 228<u>></u>150+width
subtract 150 from both sides
78<u>></u>width
width cand be 78 or less but not 0 or negative
anoth way to do it is 556<u>></u>2(150)+2width
556<u>></u>300+2width
subtract 300 from both sides
256<u>></u>2width
divide both sides by 2
78<u>></u>width
Answer:
80 games
Step-by-step explanation:
10wins/16 games=50 wins/? games
10 times 5=50 so 16 times 5 =80
10.g=16.50
10/g=800/10
g=80 games
