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Zanzabum
3 years ago
10

In your lab, a substance's temperature has been observed to follow the function T(x) = (x − 1)3 + 5. The turning point of the gr

aph is where the substance changes from a liquid to a gas. Using complete sentences in your written answer, explain to your fellow scientists how to find the turning point of this function. Hint: The turning point of the graph is similar to the vertex of a quadratic function. (10 points)
Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0
If it is a calculus question then you can find the derivative dT/dx, set it to zero and solve for x.  If this is a pre-calculus question, then you can answer is it as follows: 

The function T = x^3 has a turning point at x = 0. We can determine this simply by looking at the graph T = x^3. Therefore, (0,0) is the turning point for the graph T = x^3. The function T(x) = (x - 4)^3 + 6 will be the graph T = x^3 shifted to the right by 4 units and shifted up by 6 units. Therefore, the turning point will also shift from (0,0) to 4 units to the right and 6 units up. The turning point will be (4,6) for the function T(x) = (x - 4)^3 + 6.

You're welcome :)


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A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
20^2 + 21^2 = c^2
400 + 441 = c^2
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3 0
3 years ago
Ordered pair solution to y &gt; 3
nika2105 [10]

Answer:what I don’t get it pls explain

Step-by-step explanation:

Umm pls explain well is there supposed to be a picture or something

7 0
2 years ago
What is the value of x?
scoray [572]

Answer:

x = 54.6 m

Step-by-step explanation:

Δ MAB and Δ MNP are similar, then corresponding sides are in proportion, that is

\frac{MA}{MN} = \frac{MB}{MP} , substitute values

\frac{80.5-35}{80.5} = \frac{x}{96.6}

\frac{45.5}{80.5} = \frac{x}{96.6} ( cross- multiply )

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8 0
2 years ago
Read 2 more answers
16-5(3t-4)=8(-2t+11) How to Solve
Hunter-Best [27]

16 - 5(3t - 4) = 8(-2t + 11)        <em>use distributive property</em>: <em>a(b + c) = ab + ac</em>

16 - (5)(3t) - (5)(-4) = (8)(-2t) + (8)(11)

16 - 15t + 20 = -16t + 88

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-15t = -16t + 52            <em>add 16t to both sides</em>

t = 52

5 0
3 years ago
1.) A man invested $600 at 8% per annum for 5 years. Calculate: a.) The simple interest payable b.) The total amount of money th
Bezzdna [24]

Answer:

Following are the solution to this question:

Step-by-step explanation:

Using formula:

\text{Simple Interest} = \frac{P \times R \times T}{100} \\\\\text{ Total amount} = \text{principle}+  \text{Simple Interest}

In question (1):

Principle= \$ 600\\Rate = \ 8 \%\\Time= \ 5

In point a:

\to \frac{P \times R \times T}{100} \\\\\to \frac{(600 \times  8 \times 5)}{100}\\\\ \to  240

In point b:

\to amount = principle \ +\ simple \ interest

                 = 600 + 240 \\\\= 840

In question (2):

Principle= \$ 12,450\\Rate = \ 7.25 \%\\Time= \ 6

In point a:

\to \frac{P \times R \times T}{100} \\\\\to \frac{(12,450 \times  7.25 \times 6)}{100}\\\\ \to  5,415.75

In point b:

\to amount = principle \ +\ simple \ interest

                 = 12,450 + 5,415.75 \\\\= 17,865.75

The 3 question is incomplete, that's why it can't be solved.

7 0
3 years ago
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