The formula is
A=p (1+r)^t
A future value?
P current value 140
R rate of inflation 0.034
T time 2008-2005=3 years
A=140×(1+0.034)^(3)
A=154.77 round your answer to get
A=155
Answer:
(-2, 0.5) first
Step-by-step explanation:
X (-4, 1) → X' (-4*0.5, 1*0.5)
X'(-2, .5)
Answer: No, the money won't be enough to buy the car
Step-by-step explanation:
you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.
The principal amount, p = 300
He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So
n = 4
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for a total of 24 months. This is equivalent to 2 years. So
n = 2
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount that would be compounded at the end of n years.
A = 300(1 + (0.04/4)/4)^4×2
A = 300(1 + 0.01)^8
A = 300(1.01)^8
A = $324.857
The total amount at the end of 24 months is below the cost of the car which is $20000. So he won't have enough money to buy the car
In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.
In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.
In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...
9/17 = 18/34
15/34
6/17 = 12/34
9/34
Now we see that each number is the previous number minus 3/34, so we have a common difference of 3/34.
This would match the definition of an arithmetic sequence and NOT a geometric sequence.
5/6 * 1200/1 = 6000/6
6000/6 = 1000
Alexander pay $1000 for the computer.
