now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to
undefined.
now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.
![\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\ -------------------------------\\\\ \cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}](https://tex.z-dn.net/?f=%5Cbf%202-x%5E%7B12%7D%3D0%5Cimplies%202%3Dx%5E%7B12%7D%5Cimplies%20%5Cpm%5Csqrt%5B12%5D%7B2%7D%3Dx%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ccfrac%7Bx%5E2-9%7D%7B2-x%5E%7B12%7D%7D%5Cqquad%20%5Cboxed%7Bx%3D%5Cpm%20%5Csqrt%5B12%5D%7B2%7D%7D%5Cqquad%20%5Ccfrac%7Bx%5E2-9%7D%7B2-%28%5Cpm%5Csqrt%5B12%5D%7B2%7D%29%5E%7B12%7D%7D%5Cimplies%20%5Ccfrac%7Bx%5E2-9%7D%7B2-%5Cboxed%7B2%7D%7D%5Cimplies%20%5Cstackrel%7Bund%20efined%7D%7B%5Ccfrac%7Bx%5E2-9%7D%7B0%7D%7D)
so, the domain is all real numbers EXCEPT that one.
Answer:
So put what is order from least to greatest we have to have something to look off, you cant expect someone to just give you the answer? this could mean something for over 1 million different questions please provide more information.
Answer:
x > 9/5
Step-by-step explanation:
Step 1: Write inequality
2/3x - 1/5 > 1
Step 2: Solve for <em>x</em>
- Add 1/5 to both sides: 2/3x > 6/5
- Divide both sides by 2/3: x > 9/5
Here we see that any <em>x</em> value greater than 9/5 will work.
The answer is 12:1
note: this is often read as "12 to 1"
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Explanation
We have exactly four card that are labeled "3" and 52 cards total. So there are 52-4 = 48 cards that are not labeled "3".
From here you write the ratio 48:4 to indicate the odds against drawing a 3. There are 48 ways to lose, 4 ways to win. You list the number of ways to lose first when it comes to "odds against" type of problems.
Next step is to reduce the ratio 48:4 to get 12:1, note how I divided both parts by the GCF 4
48/4 = 12
4/4 = 1
So thats how 48:4 reduces to 12:1
If you focus on one suit, say the spades, then we have 12 cards that arent a 3 of spades while exactly one card is a 3 of spades. This is one way to see why 12:1 is the answer. If you were saying this out loud to a friend, then you might say something like "the odds against drawing a three are 12 to 1".
2.6 i believe is the answer
