For a binomial experiment in which success is defined to be a particular quality or attribute that interests us, with n=36 and p as 0.23, we can approximate p hat by a normal distribution.
Since n=36 , p=0.23 , thus q= 1-p = 1-0.23=0.77
therefore,
n*p= 36*0.23 =8.28>5
n*q = 36*0.77=27.22>5
and therefore, p hat can be approximated by a normal random variable, because n*p>5 and n*q>5.
The question is incomplete, a possible complete question is:
Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.
Suppose n = 36 and p = 0.23. Can we approximate p hat by a normal distribution? Why? (Use 2 decimal places.)
n*p = ?
n*q = ?
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Divide by 100. 350/100=3.5 which is 3 and 1/2
A = 43 • 3x + 1
= 44 •3x
= 132x
I'm not sure if I did this right.
Answer:
2
Step-by-step explanation:
2 or -2
Given:
The sequence is:
To find:
The explicit formula for the given sequence and then find the 16th term.
Solution:
We have,
The ratio between two consecutive terms are:
The given sequence has a common ratio. So, the given sequence is a geometric sequence with first term 6 and common ratio 
.
The explicit formula of a geometric sequence is:
Where, a is the first term and r is the common ratio.
Putting 
in the above formula, we get
We need to find the 16th term. So, put 
in the above formula.
Therefore, the explicit formula for the given sequence is and 16th term of the given sequence is 
.
