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castortr0y [4]
2 years ago
13

Eldrick manages wildlife samples for Ducks Unlimited. Two samples of duck populations at a migratory site are shown

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
3 0

Answer:

Eldrick can use both of these samples to find the mean frequency of each duck.

Step-by-step explanation:

Given

See attachment for samples

Required

Determine which is true

Reading through the options, we can see that Eldrick needs to evaluate the mean frequency of both samples.

To do this, both samples have to be put into consideration in order to arrive at the right value.

<em>Considering the options, we can conclude that (a) is correct.</em>

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Your friend, Susannah, manages a sandwich shop. She collects data on the number of turkey sandwiches sold per day for a week. Ex
ExtremeBDS [4]

Susannah's data are illustration of measure of central tendencies

<u>(a) The mean</u>

To calculate the mean, she needs to divide the total number of turkey sandwiches sold, by the number of days.

The total is:

\mathbf{Total = 73 +88+85+88+99+134+129}

\mathbf{Total = 696}

The number of days is:

\mathbf{Day = 7}

So, the mean is:

\mathbf{Mean =\frac{Total}{Days}}

\mathbf{Mean =\frac{696}{7}}

\mathbf{Mean =99.4}

Hence, the mean number of turkey sandwiches sold is 99.4

<u>(b) The median</u>

To calculate the median, she needs to arrange the data in ascending or descending order, then select the middle item.

In ascending order, we have: 73, 85, 88, 88, 99, 129, 134

The middle item is 88

So:

\mathbf{Median = 88}

Hence, the median number of turkey sandwiches sold is 88

<u>(c) The mode</u>

This is the data that occurs most.

From the dataset, 88 appears twice (more than others).

So:

\mathbf{Mode = 88}

Hence, the mode number of turkey sandwiches sold is 88

<u>(d) The range</u>

This is the difference between the highest and least data

From the dataset,

The highest is 134, and the least is 73

So:

\mathbf{Range =134 - 73}

\mathbf{Range =61}

Hence, the range of turkey sandwiches sold is 61

The measure that would be most helpful is the median, because it is not affected by outliers.

Read more about measures of central tendencies at:

brainly.com/question/5495004

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Step-by-step explanation:

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