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castortr0y [4]
3 years ago
13

Eldrick manages wildlife samples for Ducks Unlimited. Two samples of duck populations at a migratory site are shown

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

Eldrick can use both of these samples to find the mean frequency of each duck.

Step-by-step explanation:

Given

See attachment for samples

Required

Determine which is true

Reading through the options, we can see that Eldrick needs to evaluate the mean frequency of both samples.

To do this, both samples have to be put into consideration in order to arrive at the right value.

<em>Considering the options, we can conclude that (a) is correct.</em>

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Juanita borrowed $600 to purchase a new computer. She was charged 7% interest for two years. She used the simple interest formul
Fittoniya [83]

Answer:

The correct formula should be I= 600(0.07)(2). Juanita made a very common error, she didn't put the percentage of interest in decimal form; or she didn't put the percent sign on it so we know to put it in decimal form. Her error will make a big difference; with using her calculations the answer would be $8,400. With the correct formula the answer is $84.

<u>Hope this help!</u> :)

4 0
3 years ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
(-5,3),(0,0) what would the equation be 3/5
andrew-mc [135]
3/-5 would be the ANSEWER to your question hope I could help
3 0
3 years ago
I need help what is the answer plz
dlinn [17]

Answer:

-2.25

Step-by-step explanation:

Since there are 4 ticks between 2 numbers, we do 1/4 = 0.25

Now we find the value:

-2.25

8 0
3 years ago
13 squared? how does it mean and what is the solution?
Brut [27]
13 squered it means that =13 to the second power
13^{2}=13*13=169

6 0
3 years ago
Read 2 more answers
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