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ludmilkaskok [199]
3 years ago
6

HELP ASAP!!! On the coordinate plane below, what is the length of AB?

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
5 0

Answer:

14

Step-by-step explanation:

I just counted the squares. I hope this is helpful!

Otrada [13]3 years ago
4 0
The length is 14
Just count the spaces in between to get the result of 14
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Find k so that the following function is continuous:<br> f(x)={kx8x2if0≤x&lt;5if5≤x.
tankabanditka [31]

Check the one-sided limits:

\displaystyle \lim_{x\to5^-}f(x) = \lim_{x\to5}kx = 5k

\displaystyle \lim_{x\to5^+}f(x) = \lim_{x\to5}8x^2 = 200

If <em>f(x)</em> is to be continuous at <em>x</em> = 5, then these two limits should have the same value, which means

5<em>k</em> = 200

<em>k</em> = 200/5

<em>k</em> = 40

3 0
2 years ago
Which equation shows y=−12x+4 in standard form?
Tema [17]
The answer is the first option

6 0
2 years ago
Let L be the line parametrized by x = 2 + 2t, y = 3t, z = −1 − t. (a) Find a linear equation for the plane that is perpendicular
Elden [556K]

Answer:

Step-by-step explanation:

Given that L is a line parametrized by

x = 2 + 2t, y = 3t, z = −1 − t

The plane perpendicular to the line will have normal as this line and hence direction ratios of normal would be coefficient of t in x,y,z

i.e. (2,3,-1)

So equation of the plane would be of the form

2x+3y-z =K

Use the fact that the plane passes through (2,0,-1) and hence this point will satisfy this equation.

2(2)+3(0)-(-1) =K\\K =5

So equation is

2x+3y-z =5

b) Substitute general point of L in the plane to find the intersecting point

2(2+2t)+3t-(-1-t) =5\\4+8t+1=5\\8t=0\\t=0\\(x,y,z) = (2,0,-1)

i.e. same point given.

3 0
3 years ago
Help please, right answers :)
GuDViN [60]
B sorry if I’m wrong
6 0
3 years ago
Read 2 more answers
Please help me with this homework
satela [25.4K]

Answer:

45

Step-by-step explanation:

9x60=540

540/12= 45

3 0
3 years ago
Read 2 more answers
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