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Feliz [49]
3 years ago
11

I need help with 17 please help me.

Mathematics
1 answer:
elixir [45]3 years ago
7 0
The answers is going to be 1160 think bc not sure if we have the same kind of math
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Subtraction with different denominators examples
Rus_ich [418]

3÷3×7÷9-2÷3×9÷9

Step-by-step explanation:

3×7=21

3×9=27

21÷27=7÷9

2×9=18

3×9=27

18÷27=2÷3

7÷9-2÷3=5÷6

6 0
3 years ago
An item is regularly priced at $90. Is is on Sale for 20% off the regular price. How much (in dollars) is discounted from the re
fomenos

Answer:

18

Step-by-step explanation:

because 20% of 90 is 18

7 0
3 years ago
Read 2 more answers
Whats up guys ding dong
Artemon [7]

Answer:

Whats up, do u need help with anything?

Step-by-step explanation:

3 0
3 years ago
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Part 2: Organize Your Data
sveticcg [70]
I got you bestie

So I don’t know the other 5 points because you didn’t give the data about the age and number of US states named in 60 seconds, but using the 5coordinate points you gave, I was able to make this line of best fit.

So basically the units are counting up by 5.

The x axis is age in years and y axis is the number of US states named in 60 seconds.


Since you didn’t give me the data to make the other 5 points, I can’t really answer the last question, but from the graph that I did make, there are no points that would be considered outliers, and there are no clusters in sight.

(BTW THIS IS IMPORTANT!! - when you use the data to add the other 5 points, there might be an outlier or more then one outlier. And there might be a cluster. Just look at it after you graph the last 5 and change the answer I gave you if there is an outlier or cluster)

GRAPH IS HERE:

5 0
2 years ago
Read 2 more answers
Explain the steps for solving a triangle when you are given one side and one angle
OLga [1]

Answer:

This mean we are given two angles of a triangle and one side, which is not the side adjacent to the two given angles. Such a triangle can be solved by using Angles of a Triangle to find the other angle, and The Law of Sines to find each of the other two sides. See Solving "AAS" Triangles.

7 0
3 years ago
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