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3 years ago

What two integers have as sum of - 2 and a product of - 15?

Mathematics

2 answers:

ira [324]3 years ago

6 0

Answer:

3,-5

Step-by-step explanation:

3 - 5 = -2

3 x -5= -15

Andreyy893 years ago

5 0

Answer:

3 and -5

Step-by-step explanation:

3+(-5)= -2 because when you add a negative to a positive it is the same as subtracting

3×(-5)= -15 because a when a negative is multiplied by a positive it equals a negative

(-)×(+)=(-)

(-)×(-)=(+)

(+)×(+)=(+)

(-) means negative (+) means positive

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6. Name the polygon. Write whether it is regular<br> or not regular

slamgirl [31]

Answer:

this shape is a pentagon. this is a regular shape because all the sides are even and all the angles on the inside are also even.

Step-by-step explanation:

pls mark brainliest!

7 0

3 years ago

Mr.Eastman drew triangle JKL,with a height of 12 inches and a base of 12 inches, and triangle XLZ, with a height of 8 inches and

34kurt

Answer:

Step-by-step explanation:

Area of triangle = 1/2 × Base × Height

Mr.Eastman drew triangle JKL,with a height of 12 inches and a base of 12 inches

Area of JKL = 1/2 × 12 inches × 12 inches

= 72 Square inches

triangle XLZ, with a height of 8 inches and a base of 16 inches. Which triangle has the greater area?

5 0

3 years ago

Solve Q=3a+5ac for a

lilavasa [31]

Here is how you solve...

Q= 3a+5ac

take out the common variable.
Q= a(3+5c)

get A by its self so divide each side by (3+5c).
Q/a(3+5c)= a(3+5c)/(3+5c)

Q/a(3+5c)=A

So your answer is A= Q/a(3+5c)

hope that helped.

8 0

3 years ago

15 points!!! GEOMETRY help please!!<br> Questions attached!

dolphi86 [110]

3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

$x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o$

$Answer:\ \boxed{47^o}$

4.
Look at the picture.

Use Pythagorean theorem:

$x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8$

$Used:\ (a+b)^2=a^2+2ab+b^2$

$Answer:\ \boxed{4.8\ units}$

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}$

We have: $OP:\ y=-\dfrac{3}{2}x+b$

Now, we must find the slope of the line perpendicular to the line OP.
We know:

$k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1$

therefore

$-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}$

So. We have the answer! :)

$Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}$