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Zanzabum
3 years ago
6

5. A monument casts a 78 ft. shadow at the same time that a vertical yardstick casts a 4.5 ft. shadow. How high is the monument?

​
Mathematics
1 answer:
rodikova [14]3 years ago
5 0

Hello,

Using Thalès 's theorem:

Let's h the height of the monument.

\dfrac{1}{h} =\dfrac{4.5}{78} \\\\h=\dfrac{78}{4.5} =\dfrac{156}{9} \approx{17.3\ (ft)}

If you don't know what is the Thalès's theorem,

imagine that the similar triangles.

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xeze [42]

Answer:

2/4 and 4/8

Step-by-step explanation:

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1 1/4mi = ft, can someone explain this to me
skelet666 [1.2K]
First off, we'll convert the mixed fraction to "improper" and check about, keeping in mind that, there are 5280 feet in 1mile.

\bf \stackrel{mixed}{1\frac{1}{4}~mi}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}~mi}\\\\
-------------------------------

\bf \begin{array}{ccll}
feet&miles\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
5280&1\\
f&\frac{5}{4}
\end{array}\implies \cfrac{5280}{f}=\cfrac{1}{\quad \frac{5}{4}\quad }\implies \cfrac{5280}{f}=\cfrac{\frac{1}{1}}{\quad \frac{5}{4}\quad }
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\cfrac{5280}{f}=\cfrac{1}{1}\cdot \cfrac{4}{5}\implies \cfrac{5280}{f}=\cfrac{4}{5}\implies \cfrac{5280\cdot 5}{4}=f\implies 6600=f
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Two sides of a right triangle have the lengths 4 and 5. What is the product of the possible lengths of the third side? Express t
marishachu [46]

Answer:

19.2

Step-by-step explanation:

<u>1st Case:</u>

4 and 5 are legs of the right triangle.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+5^2=x^2

16+25=x^2

41=x^2

x=√41

√41 is about 6.4

x=6.4

<u>2nd Case</u>

5 is the hypotenuse of the right triangle and 4 is the legs.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+x^2=5^2

16+x^2=25

x^2=9

x=3

<u>Final Step</u>

We need to multiply the two possible lengths for x. So for case 1 the length of x was 6.4 and for case two the length was 3. 6.4*3=19.2

Anwser: <u>19.2</u>

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The product of 14 and the sum of 30 and an unknown number is equal to-196
Leto [7]
14 + 30 + 152 =196 14+30=44 44-196=152
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