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ExtremeBDS [4]
3 years ago
8

Evaluate 34 O A. 64 O B. 27 O C. 12 O D. 81

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0
When I evaluate it, it says it's 34 lol
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The perimeter of a rectangular note card is 18 inches. The area is 18 square inches. What are the dimensions of the note card?
4vir4ik [10]

Answer:

6 by 3

Step-by-step explanation:

a rectangle as 2 equal sides. so if we know that it is 6 by 3, then 6+6+3+3

=12+6=18

the area of a rectangle is base * height. so 6 * 3 = 18

3 0
3 years ago
Read 2 more answers
School pennants cost $18 each. Ms.Lee says she will pay $146 for 7 pennants. Is her answer reasonable?
crimeas [40]

Well, all we have to do to figure out if Ms. Lee’s offer is reasonable is multiply the unit price ($18) by 7

18 x 7 = 126

Since she offered $146, she could actually purchase 8 pennants for $144

Therefore, her answer wouldn’t be reasonable

Hope this helps you

Brainliest would be appreciated!

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3 0
3 years ago
Explain why two similar right triangles will have the same cosine ratios.
klemol [59]
ABC ,⊿PQR,select an angle ∠ACB =θ

LET θ’s (opp,adj,hypo)=(AB,BC,AC) and (PQ,QR,PR)

Then by similarity,

sinθ=AB/AC=PQ/PR ,cosθ=BC/AC=QR/PR ,tanθ=AB/BC=PQ/QR

the corresponding ratio of (adjacent side/hypotenuse),and hence

the cosine ratio must be the same
135 Views
i think it help
6 0
4 years ago
Read 2 more answers
I need help<br><br> Like asap
Tom [10]

Answer:

Step-by-step explanation:

cross multiply

-6 * 12 = 2 + z

-72 = z + 2

z = -2-72 = -74

7 0
4 years ago
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A woman 5 ft tall walks at the rate of 7.5 ft/sec away from a streetlight that is 10 ft above the ground. At what rate is the ti
lesya [120]
Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
        = (5/2)
        = 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec. 
8 0
3 years ago
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