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Usimov [2.4K]
2 years ago
13

Two old RSM students were standing 10 ft apart when they spotted Mrs. Rifkin. If they immediately run in opposite directions at

the speeds of 150 feet per minute and 160 feet per minute respectively, how many minutes will pass before they are 1870 feet apart?
Mathematics
2 answers:
ZanzabumX [31]2 years ago
8 0

Answer:

5.96 minutes :)

Katena32 [7]2 years ago
7 0

Answer:

6

Step-by-step explanation:

Seeing that the two students are running aside from

each other. We can add the speeds together.

We can also subtract 10 feet from our goal of 1870

they are already feet apart.

1870ft / (150+1650) ft per min

we are left with our answer 6

Hope this helps!

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2x + 3 + 4x + 8 = 3x - 10
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\text {Hello! Let's solve this Equation!}

\text {Your First Step is to Simplify the Equation:}

\text {(2x+4x)+(8+3)}

\text {6x+11=3x-10}

\text {The Next Step is to Subtract 3x:}

\text {6x+11-3x=3x-10-3x}\\\text {3x+11=-10}

\text {Next Step is to Subtract 11:}

\text {Q: Why Subtract 11?}

\text {A: So they cancel out. We cross them out once we subtract.}

\text {3x+11-11=-10-11}\\\text {3x=-21}

\text {The Final Step is to Divide 3:}

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