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Usimov [2.4K]
2 years ago
13

Two old RSM students were standing 10 ft apart when they spotted Mrs. Rifkin. If they immediately run in opposite directions at

the speeds of 150 feet per minute and 160 feet per minute respectively, how many minutes will pass before they are 1870 feet apart?
Mathematics
2 answers:
ZanzabumX [31]2 years ago
8 0

Answer:

5.96 minutes :)

Katena32 [7]2 years ago
7 0

Answer:

6

Step-by-step explanation:

Seeing that the two students are running aside from

each other. We can add the speeds together.

We can also subtract 10 feet from our goal of 1870

they are already feet apart.

1870ft / (150+1650) ft per min

we are left with our answer 6

Hope this helps!

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A bird sees a worm on the ground 50 m. below. The bird dives for the worm at a speed of 6 m/sec. The function h\left( t \right)
iragen [17]

<u>Given</u>:

The height of the bird at time t is given by the function h(t)=-4.9t^2+6t+50

We need to determine the time it takes the worm to be eaten by the bird.

<u>Time taken:</u>

The time can be determined by substituting h(t) = 0 in the function.

Thus, we have;

0=-4.9t^2+6t+50

Switch sides, we get;

-4.9t^2+6t+50=0

Let us solve the equation using the quadratic formula.

Thus, we get;

t=\frac{-6 \pm \sqrt{6^{2}-4(-4.9) 50}}{2(-4.9)}

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t=\frac{-6 \pm \sqrt{1016}}{-9.8}

t=\frac{-6 \pm 31.87}{-9.8}

The values of t are given by

t=\frac{-6 + 31.87}{-9.8}   and   t=\frac{-6 - 31.87}{-9.8}

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Thus, the time taken by the bird to eat the worm is t=3.9 seconds.

Hence, Option B is the correct answer.

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