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ki77a [65]
3 years ago
11

A sequence can be generated by using an=an−1+9, where a1=−5 and n is a whole number greater than 1. What are the first four term

s in the sequence?
A.−5, 4, 13, 22
B.9, 4, −1, −6
C.−5, −45, −405, −3645
D. 9, −45, 225, −1125
Mathematics
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

A

Step-by-step explanation:

For the sequence, the defining formula is given as;

an = Previous term + 9

So a2 will be -5 + 9 = 4

a3 will be 4 + 9 = 13

a4 will be 13 + 9 = 22

a5 will be 22 + 9 = 31

So the sequence of numbers will be;

-5, 4 , 13 , 22 , 31

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Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0
3 years ago
Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th
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Answer:

d

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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~~~~~~~~~~~

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x = 1020/17

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Answer:

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