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ki77a [65]
3 years ago
11

A sequence can be generated by using an=an−1+9, where a1=−5 and n is a whole number greater than 1. What are the first four term

s in the sequence?
A.−5, 4, 13, 22
B.9, 4, −1, −6
C.−5, −45, −405, −3645
D. 9, −45, 225, −1125
Mathematics
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

A

Step-by-step explanation:

For the sequence, the defining formula is given as;

an = Previous term + 9

So a2 will be -5 + 9 = 4

a3 will be 4 + 9 = 13

a4 will be 13 + 9 = 22

a5 will be 22 + 9 = 31

So the sequence of numbers will be;

-5, 4 , 13 , 22 , 31

You might be interested in
A. CPCTC<br><br> b. SAS<br><br> c. ASA<br><br> d. SSS
Lyrx [107]
a. CPCTC is your answer

CPCTC means that "Congruent Parts of a Congruent Triangle(s) are Congruent"

If ΔBRM ≅ ΔKYZ (given), then every part inside the triangle is ≅ with the corresponding side.
So, for example Line BR will be ≅  with Line KY, etc

hope this helps
7 0
3 years ago
Y=5x+7 and passes through (4,3) <br><br> the answer is y=5x-17 <br><br> How do you get the -17?
Aloiza [94]

Answer:

i do not no i do not no

Step-by-step explanation:

4 0
2 years ago
The value of 2 in 2783 is what compared to the
kykrilka [37]
We Know That This Number Is:

Two-Thousand-Seven-Hundred-Eighty-Three.

So, This tells Us That The 2 Is The Thousandths Place.

So, We Also Know That The Value Of 2 In The 2nd One Is 200. This Means That The value of the first one is 10 times larger than the value of the 2 in the second one!
3 0
3 years ago
Is the function y=<br> -<br> 9x–6 linear
alina1380 [7]

Answer:

yes

Step-by-step explanation:

5 0
3 years ago
Use logarithmic differentiation to find dy/dx
liq [111]

Answer:

dy/dx  =  (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]

Step-by-step explanation:

y = (x^2 - 3)^sinx

ln y = ln  (x^2 - 3)^sinx

ln y = sin x * ln (x^2 - 3)

1/y * dy/dx  =   sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x

1/y dy/dx =  2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)

dy/dx  =   [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y

dy/dx  =  (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]

7 0
3 years ago
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