The answer is positive 1/5. Here is a tip, when reading a graph read from left to right. If it is going up to the right it is positive. If it goes down going to the right it is negative. Also think rise/run. Count how many times it goes up(or down) then count how long the line goes.
Answer:
Step-by-step explanation:
Tienen 15 hojas de pegatinas en total.
Answer:
The first quartile is 5
The third is 8
The interquartile is the difference between the first and third quartile.
The interquartile is 3
Step-by-step explanation:
First, make a list of all the numbers. To find the first quartile, you have to first find the median. The median is the first 7 in the list.
Everything before 7 is the lower percentile of the range.
The firsr quartile is the median of the lower percentile.
The lower list is:
2,3,4,4,5,6,6,6
The median of this list is 5.
The process for finding the third quartile is the same except the list is the higher percentile which is the list of numbers above the median.
Since (f/g)(x) = f(x)/g(x) for x to be in the domain of (f/g)(x) it must be in the domain of f and in the domain of g. You also need to insure that g(x) is not zero since f(x) is divided by g(x). Thus there are 3 conditions. x must be in the domain of f: f(x) = 3x -5 and all real numbers x are in the domain of x.
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find ( f o f )(x).
( f o f )(x) = f ( f (x))
= f (2x + 3)
= 2( ) + 3 ... setting up to insert the input
= 2(2x + 3) + 3
= 4x + 6 + 3
= 4x + 9
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x).
(g o g)(x) = g(g(x))
= –( )2 + 5 ... setting up to insert the input
= –(–x2 + 5)2 + 5
= –(x4 – 10x2 + 25) + 5
= –x4 + 10x2 – 25 + 5
= –x4 + 10x2 – 20
