Answer:
b=-3
Step-by-step explanation:
If the expression simplifies to bx that means the
terms and the constant terms must be cancel out.
Simplify it first.

We know –4 + 4 will cancel out. If we simplify this expression to only an x term, then the
terms should be cancelled. Therefore, we say that 4ax^2 – x^2 = 0.

If we put a = ¼, then we can find the value of b:


if the expression is equivalent to bx
Therefore, b = –3.
The opposite is just 1. Positive 1.
Area of a triangle is 1/2 x base x height.
base = 12
Height = x+6
Area = 1/2 * 12 * x+6
Area = 1/2 * 12x * 72
Area = 6x + 36
Perimeter is the sum of the 3 sides:
x-7 + 12 + 2x+5
3x -2 + 12
3x+10
The last choice is the correct answer.
The answer is 4^-2 = 1/16
For any circle with Cartesian equation

,
we have that the centre of the circle is

, and the radius of the circle is

.
So in the case that

,
we essentially have that

.
So the centre of the circle is

, and the radius is

.