All categories

3 years ago

You pay $3 per square foot for carpeting. Which equation can be solved to find the

Mathematics

1 answer:

Kaylis [27]3 years ago

8 0

Answer:

3 * (½*2*5) = x

Step-by-step explanation:

Cost of carpeting = $3 per square foot

We have a triangular section to cover having the following dimensions:

base = 2 yd

height = 5 yd

First, let's find the area of the section = area of triangle

Area of triangle = ½*base*height

Area of the triangular section of the floor = ½*2*5

If $3 will cover 1 ft², therefore,

x will cover ½*2*5

Thus:

3 * (½*2*5) = x

You might be interested in

If the product of two positive numbers is forty eight, and one number is two greater than the other, what are the two numbers?

zaharov [31]

The two numbers are eight and six

3 0

3 years ago

X = 0.19

Luda [366]

Step-by-step explanation:

.19 = 19/100

.864 = 86.4/100

.5348 = 53.48 /100

I multiplied the decimal by 100 to get what it was before which is the same as moving two decimal places to the right and divided by 100

if any confusion ask

4 0

2 years ago

Read 2 more answers

The teacher said estimate this with out counting 1 by 1 then divide it by 20 HELP PLEASSEE

WARRIOR [948]

Well, first fin dyour best estimate mine is...600
Then after you got your best estimate divide that my 20
600/20 = 30
Hope this helped :D

7 0

3 years ago

Alexei wants to hang a mirror in his boat and put a frame around it. The mirror and frame must have an area of 19.25 square feet

zhuklara [117]

Let

x---------> the thickness of the frame in feet

At-------> Area of the mirror and the frame in square feet

we know that

$At=19.25ft^{2}$ ------> equation $1$

$At=(3+2x)*(5+2x)\\ At=3*5+3*2x+5*2x+2x*2x\\ At=15+6x+10x+4x^{2} \\ At=4x^{2} +16x+15$ --------> equation $2$

equate equation $1$ and equation $2$

$19.25=4x^{2} +16x+15\\ 4x^{2} +16x+15-19.25=0\\ 4x^{2} +16x-4.25=0$

therefore

the answer is the option

$C. 4x2 + 16x - 4.25 = 0$

5 0

3 years ago

Read 2 more answers

I don’t know how to solve this

g100num [7]

The two equations graphs intersect and the points where they are touching are belonging to both graphs therefore solutions for both equations.

(2) points (x,y) are
(-1,0) (-1)^2. +0^2=1; 1=1 ✔️
0=-1+1; 0=0✔️
(0, 1). (0)^2. +1^2=1; 1=1 ✔️
1=0+1; 1=1 ✔️

6 0

3 years ago