


Plugging in the value "
" in the above expression, we have




<h3><u>Note</u>:-</h3>

P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction

For this case we have the following equation:

Let 
We have:

By definition, given an equation of the form 
The quadratic formula, to find the solution can be written as:

In this case we have:

Substituting in the quadratic formula we have:
See attached image
Answer:
Option B
Y=4x. y=mx+b m=slope b=y intercept m=4 because it goes up 4 over 1 and 4/1=4 b=0 because it started at 0, making the equation y=4x+0 or just y=4x
Using distributive property, we get:
3x-9=0
3x=9
x=3
So, x=3. Now that was easy, huh? :)