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LekaFEV [45]
3 years ago
6

PLZ help me!!!!!!!!!!!!!!!!1

Mathematics
2 answers:
Stella [2.4K]3 years ago
8 0

Answer:

I believe the answer is b

Step-by-step explanation:

Arte-miy333 [17]3 years ago
6 0

Answer:

80

Step-by-step explanation:

16 × 5 = 80

base × height = area

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What is 62 in expended form
Mrrafil [7]
60 plus 2 is the answer  

7 0
3 years ago
Read 2 more answers
The sevth term of a geometric sequence is 108 the eight term is 36 find the common ratio
ValentinkaMS [17]

Answer:

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

\sf t_8=108 \\ \sf t_7=36

  • Common difference=d

{:}\longrightarrow\sf d=t_8-t_7

{:}\longrightarrow\sf d=108-36

{:}\longrightarrow\sf d=72

7 0
3 years ago
Please help me thank youuu
zhuklara [117]

Answer:

m<Q = 133°

Step-by-step explanation:

From the question given above, the following data were obtained:

m<P = (x + 13)°

m<Q = (10x + 13)°

m<R = (2x – 2)°

m<Q =?

Next, we shall determine the value of x. This can be obtained as follow:

m<P + m<Q + m<R = 180 (sum of angles in a triangle)

(x + 13)° + (10x + 13)° + (2x – 2)° = 180

x + 13 + 10x + 13 + 2x – 2 = 180

x + 10x + 2x + 13 + 13 – 2 = 180

13x + 24 = 180

Collect like terms

13x = 180 – 24

13x = 156

Divide both side by 13

x = 156 / 13

x = 12

Finally, we shall determine m<Q. This can be obtained as follow:

m<Q = (10x + 13)°

x = 12

m<Q = 10(12) + 13

m<Q = 120 + 13

m<Q = 133°

8 0
3 years ago
Help me pleaseeeeeeeee
Umnica [9.8K]
Because it’s an equalacteral it should be 60
7 0
3 years ago
Determine the amplitude or period as requested. Period of y = - 1/3 * sin 2x
Sedbober [7]

Answer:

Period = \pi

Step-by-step explanation:

Given

y = -\frac{1}{3} * \sin(2x)

Required

The period

A sine function is represented as:

y =A \sin(Bx + C) + D

Where

Period = \frac{2\pi}{B}

By comparing:

y =A \sin(Bx + C) + D and y = -\frac{1}{3} * \sin(2x)

B = 2

So, we have:

Period = \frac{2\pi}{2}

Period = \pi

Hence, the period of the function is \pi

3 0
3 years ago
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