Answer:
$23,330.66
Step-by-step explanation:
The compound interest function is ...
FV = P(1 +r/n)^(nt)
where P is the principal amount ($19,600), n is the number of compoundings per year (4), r is the interest rate (.035), and t is the number of years (5).
Putting these numbers into the formula and doing the arithmetic, we get ...
FV = $19,600(1 +.035/4)^(4·5) = $23,330.66
S(x) = x - 7; t(x) = 4x² - x + 3
(t · s)(x) = (4x² - x + 3)(x - 7) = (4x²)(x) + (4x²)(-7) - (x)(x) - (x)(-7) + (3)(x) + (3)(-7)
= 4x³ - 28x² - x² + 7x + 3x - 21 = 4x³ - 29x² + 10x - 21
Answer:
y=(4/3)x-4
Step-by-step explanation:
Table of ordered data
number of value
data
1 62
2 88
3 89
4 90
5 92
6 95
7 96
8 98
9 100
10 100
Range of scores: 100 - 62 = 38
Oulier: 62 => Range without the outlier = 100 - 88 = 12
Interquartile range, IQR, = difference between third quartile and first quartile: IQR = Q3 - Q1
Quartlies of all the data:
1 62
2 88
3 89 --------------- first quartile, Q1 = 89
4 90
5 92
------------------------------------------ median, Q2 = (95 + 92) / 2 = 93.5
6 95
7 96
8 98 ---------------- third quartile, Q3 = 98
9 100
10 100
=> IQR = 98 - 89 = 9 : the interquartle range is 9
Quartlies without the outlier:
2 88
3 89
------------------------------------- first quartile, Q1 = (89 + 90) / 2 = 89.5
4 90
5 92
6 95 --------------- median, Q2 = 95
7 96
8 98
------------------------------------ third quartile, Q3 = (98 + 100) / 2 = 99
9 100
10 100
=> IQR = Q3 - Q1 = 99 - 89.5 = : the interquartle range without the outlier is 9.5
Therefore, the outlier impacts more the range than it impacts the IQR.
THE ONLY STATEMENT THAT IS FALSE IS THE NUMBER 5.
Answer:
for #2 I'm pretty sure he makes $10 per hour
