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Allushta [10]
3 years ago
11

Evaluate arccos (-1/2)

Mathematics
1 answer:
Crazy boy [7]3 years ago
3 0

Answer:

120 degrees

Step-by-step explanation:

plugged into calculator

cos inverse of -1/2

Please mark Brainliest if you feel like it:)

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4/16

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You ate 4 slice of the 16 slice pizza

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There were 624 envelopes to be sorted into 8 different mail bags. if the same number of envelopes will be in each bag how many e
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Step-by-step explanation:

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4 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
nirvana33 [79]

Answer:

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.1 = 0.99, so z = 1.28

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.28*\frac{4.1}{\sqrt{840}} = 0.2

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.

The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

3 0
4 years ago
A grocer wants to make a 10-pound mixture of cash tans peanuts that he can sell for $3.29 per pound. If cashews cost $5.60 per p
bagirrra123 [75]
Label each nut with a variable, c = cashews, p = peanuts.....
for a 10-pound mix, you will need c + p = 10
the price for 10-pounds would become 3.29 x 10 = 32.90 

You will need an unknown amount of cashews at 5.60/lb and an unknown amount of peanuts at 2.30/lbs to get your full 10 pounds valued at 32.90
5.60c + 2.30p = 32.90 

Now you 2 have a system of 2 equations and 2 unknowns
c + p = 105.6c + 2.3p = 32.9utilize substitution to solve:p = 10-c
5.6 c + 2.3 (10-c) = 32.9
solve for c then substitute back into c + p = 10 to solve for P

Hope this helps!
3 0
3 years ago
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