Question

-x^2 +9x-12 in vertex form please help !!!

Answer 1

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this firm use the method of completing the square

Factor out - 1 from each term

y = - (x² - 9x + 12)$\frac{33}{4}$

To complete the square

add/subtract (half the coefficient of the x- term )² to x² - 9x

y = - (x² + 2( - $\frac{9}{2}$)x + $\frac{81}{4}$ - $\frac{81}{4}$ + 12 )

  = - ( (x - $\frac{9}{2}$)² - $\frac{33}{4}$ )

y = - (x - $\frac{9}{2}$ )² + $\frac{33}{4}$ ← in vertex form